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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 964 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹4400 grow to in 1 year at 12% per year compound interest (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹43200 at 15% per year for 2 years (in ₹)?
  3. 3.Find the compound interest on ₹34800 at 25% per year for 2 years, compounded every year (in ₹).
  4. 4.A town has 49600 people. The population grows by 25% every year. What will the population be after 3 years?
  5. 5.A scooter is worth ₹45000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  6. 6.Find the compound interest on ₹28500 at 25% per year for 1 year, compounded every year (in ₹).
  7. 7.A scooter is worth ₹10800. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  8. 8.Find the compound interest on ₹24000 at 25% per year for 3 years, compounded every year (in ₹).
  9. 9.A scooter is worth ₹46700. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  10. 10.Find the compound interest on ₹12800 at 5% per year for 1 year, compounded every year (in ₹).
  11. 11.A town has 32500 people. The population grows by 4% every year. What will the population be after 2 years?
  12. 12.A scooter is worth ₹12500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  13. 13.Find the compound interest on ₹22500 at 25% per year for 1 year, compounded every year (in ₹).
  14. 14.Find the compound interest on ₹2000 at 10% per year for 3 years, compounded every year (in ₹).
  15. 15.Find the compound interest on ₹8700 at 5% per year for 1 year, compounded every year (in ₹).
  16. 16.A town has 50600 people. The population grows by 20% every year. What will the population be after 2 years?
  17. 17.A scooter is worth ₹47300. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  18. 18.What amount will ₹46400 grow to in 2 years at 25% per year compound interest (in ₹)?
  19. 19.Find the compound interest on ₹33000 at 10% per year for 3 years, compounded every year (in ₹).
  20. 20.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
  21. 21.What amount will ₹18800 grow to in 1 year at 10% per year compound interest (in ₹)?
  22. 22.Find the compound interest on ₹30000 at 20% per year for 1 year, compounded every year (in ₹).
  23. 23.Find the compound interest on ₹43200 at 25% per year for 3 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹23800 at 15% per year for 1 year, compounded every year (in ₹).
  25. 25.What is the difference between the compound interest and the simple interest on ₹45200 at 15% per year for 2 years (in ₹)?
  26. 26.Find the compound interest on ₹49000 at 10% per year for 3 years, compounded every year (in ₹).
  27. 27.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
  28. 28.Find the compound interest on ₹25200 at 25% per year for 2 years, compounded every year (in ₹).
  29. 29.What amount will ₹45200 grow to in 2 years at 5% per year compound interest (in ₹)?
  30. 30.Find the compound interest on ₹19600 at 5% per year for 2 years, compounded every year (in ₹).
  31. 31.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
  32. 32.A scooter is worth ₹10000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  33. 33.Find the compound interest on ₹14000 at 25% per year for 2 years, compounded every year (in ₹).
  34. 34.Find the compound interest on ₹31600 at 15% per year for 1 year, compounded every year (in ₹).
  35. 35.Find the compound interest on ₹12500 at 10% per year for 2 years, compounded every year (in ₹).
  36. 36.A scooter is worth ₹10500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹32400 at 25% per year for 2 years (in ₹)?
  38. 38.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  39. 39.Find the compound interest on ₹24700 at 10% per year for 2 years, compounded every year (in ₹).
  40. 40.Find the compound interest on ₹18600 at 20% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 4928
  2. 972
  3. 19575
  4. 96875
  5. 32805
  6. 7125
  7. 6912
  8. 22875
  9. 42964
  10. 640
  11. 35152
  12. 11520
  13. 5625
  14. 662
  15. 435
  16. 72864
  17. 35475
  18. 72500
  19. 10923
  20. 60
  21. 20680
  22. 6000
  23. 41175
  24. 3570
  25. 1017
  26. 16219
  27. 256
  28. 14175
  29. 49833
  30. 2009
  31. 9261
  32. 7744
  33. 7875
  34. 4740
  35. 2625
  36. 5376
  37. 2025
  38. 9826
  39. 5187
  40. 3720

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