← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 98 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A scooter is worth ₹13300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  2. 2.What amount will ₹13500 grow to in 1 year at 10% per year compound interest (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹42100 at 20% per year for 2 years (in ₹)?
  4. 4.Find the compound interest on ₹51500 at 10% per year for 1 year, compounded every year (in ₹).
  5. 5.What amount will ₹30000 grow to in 3 years at 10% per year compound interest (in ₹)?
  6. 6.What amount will ₹58000 grow to in 1 year at 5% per year compound interest (in ₹)?
  7. 7.A scooter is worth ₹37700. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹13900 at 20% per year for 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹42800 at 15% per year for 2 years (in ₹)?
  10. 10.Find the compound interest on ₹11600 at 15% per year for 2 years, compounded every year (in ₹).
  11. 11.What amount will ₹32000 grow to in 2 years at 5% per year compound interest (in ₹)?
  12. 12.A town has 30000 people. The population grows by 4% every year. What will the population be after 2 years?
  13. 13.A scooter is worth ₹42700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹48000 at 5% per year for 2 years (in ₹)?
  15. 15.What amount will ₹45000 grow to in 2 years at 12% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹6000 at 25% per year for 2 years, compounded every year (in ₹).
  17. 17.What amount will ₹12500 grow to in 2 years at 4% per year compound interest (in ₹)?
  18. 18.What amount will ₹34500 grow to in 3 years at 20% per year compound interest (in ₹)?
  19. 19.Find the compound interest on ₹14300 at 10% per year for 1 year, compounded every year (in ₹).
  20. 20.A town has 15000 people. The population grows by 12% every year. What will the population be after 2 years?
  21. 21.A scooter is worth ₹25000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  22. 22.What amount will ₹15200 grow to in 2 years at 25% per year compound interest (in ₹)?
  23. 23.A town has 25700 people. The population grows by 12% every year. What will the population be after 1 year?
  24. 24.A town has 25400 people. The population grows by 12% every year. What will the population be after 1 year?
  25. 25.What is the difference between the compound interest and the simple interest on ₹3600 at 5% per year for 2 years (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹48800 at 5% per year for 2 years (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹30400 at 5% per year for 2 years (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹60000 at 15% per year for 2 years (in ₹)?
  29. 29.A town has 3600 people. The population grows by 10% every year. What will the population be after 2 years?
  30. 30.What amount will ₹6200 grow to in 1 year at 5% per year compound interest (in ₹)?
  31. 31.Find the compound interest on ₹18100 at 20% per year for 2 years, compounded every year (in ₹).
  32. 32.A town has 45000 people. The population grows by 8% every year. What will the population be after 2 years?
  33. 33.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
  34. 34.A scooter is worth ₹34700. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  35. 35.A town has 51200 people. The population grows by 25% every year. What will the population be after 3 years?
  36. 36.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
  37. 37.Find the compound interest on ₹39700 at 15% per year for 1 year, compounded every year (in ₹).
  38. 38.Find the compound interest on ₹60000 at 10% per year for 1 year, compounded every year (in ₹).
  39. 39.What is the difference between the compound interest and the simple interest on ₹28600 at 10% per year for 2 years (in ₹)?
  40. 40.What amount will ₹54100 grow to in 1 year at 8% per year compound interest (in ₹)?

Answer key

  1. 12635
  2. 14850
  3. 1684
  4. 5150
  5. 39930
  6. 60900
  7. 35815
  8. 556
  9. 963
  10. 3741
  11. 35280
  12. 32448
  13. 38430
  14. 120
  15. 56448
  16. 3375
  17. 13520
  18. 59616
  19. 1430
  20. 18816
  21. 23040
  22. 23750
  23. 28784
  24. 28448
  25. 9
  26. 122
  27. 76
  28. 1350
  29. 4356
  30. 6510
  31. 7964
  32. 52488
  33. 20
  34. 33312
  35. 100000
  36. 176
  37. 5955
  38. 6000
  39. 286
  40. 58428

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets