Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹40000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 2.A town has 21000 people. The population grows by 20% every year. What will the population be after 3 years?
- 3.What is the difference between the compound interest and the simple interest on ₹26400 at 25% per year for 2 years (in ₹)?
- 4.Find the compound interest on ₹32900 at 10% per year for 1 year, compounded every year (in ₹).
- 5.Find the compound interest on ₹53400 at 20% per year for 2 years, compounded every year (in ₹).
- 6.A town has 22500 people. The population grows by 8% every year. What will the population be after 2 years?
- 7.What is the difference between the compound interest and the simple interest on ₹27600 at 5% per year for 2 years (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹5200 at 5% per year for 2 years (in ₹)?
- 10.A scooter is worth ₹12500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 11.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 12.Find the compound interest on ₹50500 at 4% per year for 1 year, compounded every year (in ₹).
- 13.Find the compound interest on ₹31900 at 8% per year for 1 year, compounded every year (in ₹).
- 14.Find the compound interest on ₹60000 at 10% per year for 3 years, compounded every year (in ₹).
- 15.What amount will ₹35000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 16.Find the compound interest on ₹23600 at 5% per year for 2 years, compounded every year (in ₹).
- 17.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 18.Find the compound interest on ₹51200 at 15% per year for 2 years, compounded every year (in ₹).
- 19.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
- 20.A town has 32000 people. The population grows by 25% every year. What will the population be after 2 years?
- 21.A town has 24400 people. The population grows by 10% every year. What will the population be after 1 year?
- 22.What is the difference between the compound interest and the simple interest on ₹47500 at 10% per year for 2 years (in ₹)?
- 23.Find the compound interest on ₹24000 at 25% per year for 3 years, compounded every year (in ₹).
- 24.Find the compound interest on ₹15000 at 12% per year for 2 years, compounded every year (in ₹).
- 25.Find the compound interest on ₹7600 at 5% per year for 2 years, compounded every year (in ₹).
- 26.What amount will ₹16500 grow to in 2 years at 20% per year compound interest (in ₹)?
- 27.What amount will ₹5200 grow to in 2 years at 10% per year compound interest (in ₹)?
- 28.What amount will ₹2000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 29.What amount will ₹5000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 30.A scooter is worth ₹25000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹4800 at 15% per year for 2 years (in ₹)?
- 32.What amount will ₹25900 grow to in 1 year at 20% per year compound interest (in ₹)?
- 33.Find the compound interest on ₹36000 at 10% per year for 1 year, compounded every year (in ₹).
- 34.What amount will ₹17200 grow to in 2 years at 25% per year compound interest (in ₹)?
- 35.A town has 50800 people. The population grows by 15% every year. What will the population be after 2 years?
- 36.What amount will ₹32600 grow to in 2 years at 10% per year compound interest (in ₹)?
- 37.What is the difference between the compound interest and the simple interest on ₹21000 at 20% per year for 2 years (in ₹)?
- 38.A scooter is worth ₹26700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 39.A town has 3700 people. The population grows by 12% every year. What will the population be after 1 year?
- 40.What amount will ₹42100 grow to in 2 years at 20% per year compound interest (in ₹)?
Answer key
- 36864
- 36288
- 1650
- 3290
- 23496
- 26244
- 69
- 128
- 13
- 10580
- 65856
- 2020
- 2552
- 19860
- 37856
- 2419
- 9826
- 16512
- 92
- 50000
- 26840
- 475
- 22875
- 3816
- 779
- 23760
- 6292
- 2662
- 5832
- 23040
- 108
- 31080
- 3600
- 26875
- 67183
- 39446
- 840
- 24030
- 4144
- 60624
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