Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 987 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹37000 grow to in 1 year at 20% per year compound interest (in ₹)?
2. 2.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
3. 3.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹14600 at 25% per year for 1 year, compounded every year (in ₹).
6. 6.Find the compound interest on ₹57300 at 10% per year for 1 year, compounded every year (in ₹).
7. 7.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹17200 at 25% per year for 2 years (in ₹)?
9. 9.What amount will ₹2200 grow to in 1 year at 4% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹34000 at 5% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹24000 at 25% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹46900 at 20% per year for 2 years, compounded every year (in ₹).
13. 13.Find the compound interest on ₹37900 at 5% per year for 1 year, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹3000 at 10% per year for 2 years (in ₹)?
15. 15.A town has 32000 people. The population grows by 5% every year. What will the population be after 3 years?
16. 16.A town has 47900 people. The population grows by 10% every year. What will the population be after 2 years?
17. 17.What amount will ₹35500 grow to in 1 year at 4% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹25600 at 5% per year for 2 years (in ₹)?
19. 19.A scooter is worth ₹3000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
20. 20.What amount will ₹45200 grow to in 1 year at 10% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹4700 at 10% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
23. 23.Find the compound interest on ₹51400 at 20% per year for 2 years, compounded every year (in ₹).
24. 24.What amount will ₹44800 grow to in 2 years at 20% per year compound interest (in ₹)?
25. 25.What amount will ₹9000 grow to in 1 year at 4% per year compound interest (in ₹)?
26. 26.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹7500 at 12% per year for 2 years, compounded every year (in ₹).
28. 28.Find the compound interest on ₹15000 at 10% per year for 1 year, compounded every year (in ₹).
29. 29.What amount will ₹14600 grow to in 1 year at 5% per year compound interest (in ₹)?
30. 30.A scooter is worth ₹40000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
31. 31.A scooter is worth ₹24300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
32. 32.What amount will ₹45900 grow to in 1 year at 10% per year compound interest (in ₹)?
33. 33.A town has 44400 people. The population grows by 5% every year. What will the population be after 2 years?
34. 34.What is the difference between the compound interest and the simple interest on ₹5600 at 5% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹40700 at 10% per year for 1 year, compounded every year (in ₹).
36. 36.Find the compound interest on ₹38900 at 4% per year for 1 year, compounded every year (in ₹).
37. 37.A scooter is worth ₹12500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
38. 38.What amount will ₹34700 grow to in 1 year at 5% per year compound interest (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹37300 at 20% per year for 2 years (in ₹)?
40. 40.What amount will ₹24300 grow to in 1 year at 25% per year compound interest (in ₹)?

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