Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 988 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹3400 at 10% per year for 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹52100 at 10% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹46700 at 25% per year for 1 year, compounded every year (in ₹).
4. 4.What amount will ₹22400 grow to in 1 year at 4% per year compound interest (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹9600 at 10% per year for 2 years (in ₹)?
6. 6.What amount will ₹4400 grow to in 1 year at 25% per year compound interest (in ₹)?
7. 7.What amount will ₹50000 grow to in 2 years at 5% per year compound interest (in ₹)?
8. 8.Find the compound interest on ₹27300 at 5% per year for 1 year, compounded every year (in ₹).
9. 9.A town has 18400 people. The population grows by 10% every year. What will the population be after 2 years?
10. 10.A town has 21200 people. The population grows by 5% every year. What will the population be after 1 year?
11. 11.Find the compound interest on ₹33500 at 10% per year for 1 year, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹12000 at 25% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹31200 at 10% per year for 2 years, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
16. 16.A town has 28700 people. The population grows by 10% every year. What will the population be after 2 years?
17. 17.What amount will ₹7500 grow to in 2 years at 12% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
19. 19.A scooter is worth ₹27200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
20. 20.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹28500 at 10% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹48000 at 25% per year for 2 years (in ₹)?
23. 23.A scooter is worth ₹47500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
24. 24.What amount will ₹13600 grow to in 2 years at 25% per year compound interest (in ₹)?
25. 25.A town has 18300 people. The population grows by 25% every year. What will the population be after 1 year?
26. 26.Find the compound interest on ₹51500 at 20% per year for 3 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹34800 at 15% per year for 2 years, compounded every year (in ₹).
28. 28.What amount will ₹50000 grow to in 2 years at 4% per year compound interest (in ₹)?
29. 29.A scooter is worth ₹13700. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
30. 30.Find the compound interest on ₹33200 at 15% per year for 1 year, compounded every year (in ₹).
31. 31.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
32. 32.What amount will ₹32500 grow to in 2 years at 4% per year compound interest (in ₹)?
33. 33.A town has 34600 people. The population grows by 5% every year. What will the population be after 1 year?
34. 34.Find the compound interest on ₹38300 at 15% per year for 1 year, compounded every year (in ₹).
35. 35.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
36. 36.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
38. 38.Find the compound interest on ₹59100 at 12% per year for 1 year, compounded every year (in ₹).
39. 39.Find the compound interest on ₹34400 at 25% per year for 1 year, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹20000 at 5% per year for 2 years (in ₹)?

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