← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 989 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹59200 at 25% per year for 3 years, compounded every year (in ₹).
  2. 2.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
  3. 3.Find the compound interest on ₹25700 at 4% per year for 1 year, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
  5. 5.A scooter is worth ₹55000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  6. 6.Find the compound interest on ₹28000 at 20% per year for 3 years, compounded every year (in ₹).
  7. 7.A town has 41300 people. The population grows by 8% every year. What will the population be after 1 year?
  8. 8.What amount will ₹24000 grow to in 3 years at 25% per year compound interest (in ₹)?
  9. 9.Find the compound interest on ₹53000 at 20% per year for 2 years, compounded every year (in ₹).
  10. 10.What is the difference between the compound interest and the simple interest on ₹29200 at 5% per year for 2 years (in ₹)?
  11. 11.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
  12. 12.A town has 8000 people. The population grows by 15% every year. What will the population be after 2 years?
  13. 13.A scooter is worth ₹14400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  14. 14.Find the compound interest on ₹14200 at 20% per year for 1 year, compounded every year (in ₹).
  15. 15.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
  16. 16.What is the difference between the compound interest and the simple interest on ₹13200 at 20% per year for 2 years (in ₹)?
  17. 17.A town has 59000 people. The population grows by 10% every year. What will the population be after 3 years?
  18. 18.A town has 55000 people. The population grows by 15% every year. What will the population be after 1 year?
  19. 19.What amount will ₹34400 grow to in 2 years at 25% per year compound interest (in ₹)?
  20. 20.A scooter is worth ₹30500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  21. 21.Find the compound interest on ₹33900 at 12% per year for 1 year, compounded every year (in ₹).
  22. 22.Find the compound interest on ₹59200 at 5% per year for 1 year, compounded every year (in ₹).
  23. 23.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
  24. 24.What amount will ₹21000 grow to in 3 years at 20% per year compound interest (in ₹)?
  25. 25.A town has 27900 people. The population grows by 5% every year. What will the population be after 1 year?
  26. 26.Find the compound interest on ₹6700 at 20% per year for 1 year, compounded every year (in ₹).
  27. 27.What amount will ₹55000 grow to in 3 years at 10% per year compound interest (in ₹)?
  28. 28.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  29. 29.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
  30. 30.A town has 25600 people. The population grows by 25% every year. What will the population be after 3 years?
  31. 31.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
  32. 32.What amount will ₹51400 grow to in 1 year at 12% per year compound interest (in ₹)?
  33. 33.What amount will ₹37300 grow to in 1 year at 10% per year compound interest (in ₹)?
  34. 34.Find the compound interest on ₹31100 at 12% per year for 1 year, compounded every year (in ₹).
  35. 35.Find the compound interest on ₹41600 at 20% per year for 2 years, compounded every year (in ₹).
  36. 36.What amount will ₹20700 grow to in 1 year at 10% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹58400 at 8% per year for 1 year, compounded every year (in ₹).
  38. 38.What is the difference between the compound interest and the simple interest on ₹47200 at 10% per year for 2 years (in ₹)?
  39. 39.A town has 32300 people. The population grows by 20% every year. What will the population be after 1 year?
  40. 40.What amount will ₹31600 grow to in 2 years at 5% per year compound interest (in ₹)?

Answer key

  1. 56425
  2. 256
  3. 1028
  4. 612
  5. 46552
  6. 20384
  7. 44604
  8. 46875
  9. 23320
  10. 73
  11. 7566
  12. 10580
  13. 12960
  14. 2840
  15. 24
  16. 528
  17. 78529
  18. 63250
  19. 53750
  20. 15616
  21. 4068
  22. 2960
  23. 5044
  24. 36288
  25. 29295
  26. 1340
  27. 73205
  28. 18522
  29. 7632
  30. 50000
  31. 9261
  32. 57568
  33. 41030
  34. 3732
  35. 18304
  36. 22770
  37. 4672
  38. 472
  39. 38760
  40. 34839

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets