Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹59200 at 25% per year for 3 years, compounded every year (in ₹).
- 2.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
- 3.Find the compound interest on ₹25700 at 4% per year for 1 year, compounded every year (in ₹).
- 4.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
- 5.A scooter is worth ₹55000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 6.Find the compound interest on ₹28000 at 20% per year for 3 years, compounded every year (in ₹).
- 7.A town has 41300 people. The population grows by 8% every year. What will the population be after 1 year?
- 8.What amount will ₹24000 grow to in 3 years at 25% per year compound interest (in ₹)?
- 9.Find the compound interest on ₹53000 at 20% per year for 2 years, compounded every year (in ₹).
- 10.What is the difference between the compound interest and the simple interest on ₹29200 at 5% per year for 2 years (in ₹)?
- 11.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 12.A town has 8000 people. The population grows by 15% every year. What will the population be after 2 years?
- 13.A scooter is worth ₹14400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 14.Find the compound interest on ₹14200 at 20% per year for 1 year, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹13200 at 20% per year for 2 years (in ₹)?
- 17.A town has 59000 people. The population grows by 10% every year. What will the population be after 3 years?
- 18.A town has 55000 people. The population grows by 15% every year. What will the population be after 1 year?
- 19.What amount will ₹34400 grow to in 2 years at 25% per year compound interest (in ₹)?
- 20.A scooter is worth ₹30500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 21.Find the compound interest on ₹33900 at 12% per year for 1 year, compounded every year (in ₹).
- 22.Find the compound interest on ₹59200 at 5% per year for 1 year, compounded every year (in ₹).
- 23.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 24.What amount will ₹21000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 25.A town has 27900 people. The population grows by 5% every year. What will the population be after 1 year?
- 26.Find the compound interest on ₹6700 at 20% per year for 1 year, compounded every year (in ₹).
- 27.What amount will ₹55000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 28.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 29.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
- 30.A town has 25600 people. The population grows by 25% every year. What will the population be after 3 years?
- 31.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 32.What amount will ₹51400 grow to in 1 year at 12% per year compound interest (in ₹)?
- 33.What amount will ₹37300 grow to in 1 year at 10% per year compound interest (in ₹)?
- 34.Find the compound interest on ₹31100 at 12% per year for 1 year, compounded every year (in ₹).
- 35.Find the compound interest on ₹41600 at 20% per year for 2 years, compounded every year (in ₹).
- 36.What amount will ₹20700 grow to in 1 year at 10% per year compound interest (in ₹)?
- 37.Find the compound interest on ₹58400 at 8% per year for 1 year, compounded every year (in ₹).
- 38.What is the difference between the compound interest and the simple interest on ₹47200 at 10% per year for 2 years (in ₹)?
- 39.A town has 32300 people. The population grows by 20% every year. What will the population be after 1 year?
- 40.What amount will ₹31600 grow to in 2 years at 5% per year compound interest (in ₹)?
Answer key
- 56425
- 256
- 1028
- 612
- 46552
- 20384
- 44604
- 46875
- 23320
- 73
- 7566
- 10580
- 12960
- 2840
- 24
- 528
- 78529
- 63250
- 53750
- 15616
- 4068
- 2960
- 5044
- 36288
- 29295
- 1340
- 73205
- 18522
- 7632
- 50000
- 9261
- 57568
- 41030
- 3732
- 18304
- 22770
- 4672
- 472
- 38760
- 34839
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