Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 990 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹24800 grow to in 2 years at 5% per year compound interest (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹57000 at 10% per year for 3 years, compounded every year (in ₹).
4. 4.A scooter is worth ₹37000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
5. 5.A town has 29800 people. The population grows by 25% every year. What will the population be after 1 year?
6. 6.Find the compound interest on ₹7500 at 12% per year for 2 years, compounded every year (in ₹).
7. 7.What amount will ₹13900 grow to in 2 years at 10% per year compound interest (in ₹)?
8. 8.What amount will ₹8800 grow to in 2 years at 5% per year compound interest (in ₹)?
9. 9.A town has 42800 people. The population grows by 4% every year. What will the population be after 1 year?
10. 10.A town has 23200 people. The population grows by 5% every year. What will the population be after 2 years?
11. 11.A town has 24400 people. The population grows by 10% every year. What will the population be after 2 years?
12. 12.A town has 21000 people. The population grows by 10% every year. What will the population be after 3 years?
13. 13.Find the compound interest on ₹31100 at 5% per year for 1 year, compounded every year (in ₹).
14. 14.A scooter is worth ₹22500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹12800 at 5% per year for 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹9100 at 20% per year for 2 years (in ₹)?
17. 17.What amount will ₹33200 grow to in 1 year at 4% per year compound interest (in ₹)?
18. 18.What amount will ₹32600 grow to in 2 years at 10% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹11500 at 20% per year for 2 years (in ₹)?
20. 20.A town has 5000 people. The population grows by 20% every year. What will the population be after 1 year?
21. 21.Find the compound interest on ₹33200 at 5% per year for 2 years, compounded every year (in ₹).
22. 22.Find the compound interest on ₹39200 at 15% per year for 1 year, compounded every year (in ₹).
23. 23.What amount will ₹11500 grow to in 1 year at 25% per year compound interest (in ₹)?
24. 24.What amount will ₹40000 grow to in 2 years at 12% per year compound interest (in ₹)?
25. 25.What amount will ₹9600 grow to in 3 years at 25% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹53400 at 4% per year for 1 year, compounded every year (in ₹).
27. 27.Find the compound interest on ₹46300 at 25% per year for 1 year, compounded every year (in ₹).
28. 28.A town has 20100 people. The population grows by 20% every year. What will the population be after 2 years?
29. 29.What is the difference between the compound interest and the simple interest on ₹47600 at 5% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹25300 at 5% per year for 1 year, compounded every year (in ₹).
31. 31.A scooter is worth ₹50400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹16000 at 20% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹27500 at 4% per year for 2 years, compounded every year (in ₹).
34. 34.What is the difference between the compound interest and the simple interest on ₹56000 at 25% per year for 2 years (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹12000 at 25% per year for 2 years (in ₹)?
36. 36.Find the compound interest on ₹2400 at 8% per year for 1 year, compounded every year (in ₹).
37. 37.What amount will ₹13000 grow to in 3 years at 10% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹47300 at 10% per year for 2 years, compounded every year (in ₹).
39. 39.What amount will ₹30200 grow to in 2 years at 10% per year compound interest (in ₹)?
40. 40.A town has 39000 people. The population grows by 10% every year. What will the population be after 3 years?

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