Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
- 2.Find the compound interest on ₹53200 at 25% per year for 2 years, compounded every year (in ₹).
- 3.What is the difference between the compound interest and the simple interest on ₹28400 at 15% per year for 2 years (in ₹)?
- 4.A town has 37500 people. The population grows by 4% every year. What will the population be after 2 years?
- 5.What is the difference between the compound interest and the simple interest on ₹33200 at 15% per year for 2 years (in ₹)?
- 6.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 7.What amount will ₹55000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 8.What amount will ₹32400 grow to in 2 years at 5% per year compound interest (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹30000 at 25% per year for 2 years (in ₹)?
- 10.What amount will ₹51200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 11.What amount will ₹11300 grow to in 1 year at 8% per year compound interest (in ₹)?
- 12.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 13.Find the compound interest on ₹52500 at 4% per year for 2 years, compounded every year (in ₹).
- 14.What amount will ₹4900 grow to in 1 year at 25% per year compound interest (in ₹)?
- 15.Find the compound interest on ₹20100 at 4% per year for 1 year, compounded every year (in ₹).
- 16.A town has 6800 people. The population grows by 25% every year. What will the population be after 2 years?
- 17.A town has 40000 people. The population grows by 10% every year. What will the population be after 2 years?
- 18.Find the compound interest on ₹55000 at 12% per year for 1 year, compounded every year (in ₹).
- 19.Find the compound interest on ₹18200 at 10% per year for 2 years, compounded every year (in ₹).
- 20.A scooter is worth ₹7500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 21.Find the compound interest on ₹37200 at 25% per year for 2 years, compounded every year (in ₹).
- 22.A scooter is worth ₹54500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 23.What amount will ₹3600 grow to in 2 years at 15% per year compound interest (in ₹)?
- 24.A town has 27500 people. The population grows by 12% every year. What will the population be after 2 years?
- 25.What is the difference between the compound interest and the simple interest on ₹58500 at 10% per year for 2 years (in ₹)?
- 26.Find the compound interest on ₹2700 at 10% per year for 2 years, compounded every year (in ₹).
- 27.What amount will ₹57100 grow to in 1 year at 12% per year compound interest (in ₹)?
- 28.What is the difference between the compound interest and the simple interest on ₹37900 at 20% per year for 2 years (in ₹)?
- 29.A scooter is worth ₹29000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 30.What amount will ₹7500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 31.A town has 15800 people. The population grows by 4% every year. What will the population be after 1 year?
- 32.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
- 33.A scooter is worth ₹46600. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
- 35.Find the compound interest on ₹19000 at 4% per year for 1 year, compounded every year (in ₹).
- 36.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 37.What amount will ₹22300 grow to in 1 year at 5% per year compound interest (in ₹)?
- 38.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
- 39.Find the compound interest on ₹38700 at 20% per year for 1 year, compounded every year (in ₹).
- 40.Find the compound interest on ₹37600 at 10% per year for 2 years, compounded every year (in ₹).
Answer key
- 25
- 29925
- 639
- 40560
- 747
- 48668
- 64152
- 35721
- 1875
- 100000
- 12204
- 20577
- 4284
- 6125
- 804
- 10625
- 48400
- 6600
- 3822
- 3840
- 20925
- 27904
- 4761
- 34496
- 585
- 567
- 63952
- 1516
- 21141
- 8748
- 16432
- 1836
- 29824
- 80
- 760
- 55566
- 23415
- 12501
- 7740
- 7896
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