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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 991 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
  2. 2.Find the compound interest on ₹53200 at 25% per year for 2 years, compounded every year (in ₹).
  3. 3.What is the difference between the compound interest and the simple interest on ₹28400 at 15% per year for 2 years (in ₹)?
  4. 4.A town has 37500 people. The population grows by 4% every year. What will the population be after 2 years?
  5. 5.What is the difference between the compound interest and the simple interest on ₹33200 at 15% per year for 2 years (in ₹)?
  6. 6.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
  7. 7.What amount will ₹55000 grow to in 2 years at 8% per year compound interest (in ₹)?
  8. 8.What amount will ₹32400 grow to in 2 years at 5% per year compound interest (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹30000 at 25% per year for 2 years (in ₹)?
  10. 10.What amount will ₹51200 grow to in 3 years at 25% per year compound interest (in ₹)?
  11. 11.What amount will ₹11300 grow to in 1 year at 8% per year compound interest (in ₹)?
  12. 12.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  13. 13.Find the compound interest on ₹52500 at 4% per year for 2 years, compounded every year (in ₹).
  14. 14.What amount will ₹4900 grow to in 1 year at 25% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹20100 at 4% per year for 1 year, compounded every year (in ₹).
  16. 16.A town has 6800 people. The population grows by 25% every year. What will the population be after 2 years?
  17. 17.A town has 40000 people. The population grows by 10% every year. What will the population be after 2 years?
  18. 18.Find the compound interest on ₹55000 at 12% per year for 1 year, compounded every year (in ₹).
  19. 19.Find the compound interest on ₹18200 at 10% per year for 2 years, compounded every year (in ₹).
  20. 20.A scooter is worth ₹7500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  21. 21.Find the compound interest on ₹37200 at 25% per year for 2 years, compounded every year (in ₹).
  22. 22.A scooter is worth ₹54500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  23. 23.What amount will ₹3600 grow to in 2 years at 15% per year compound interest (in ₹)?
  24. 24.A town has 27500 people. The population grows by 12% every year. What will the population be after 2 years?
  25. 25.What is the difference between the compound interest and the simple interest on ₹58500 at 10% per year for 2 years (in ₹)?
  26. 26.Find the compound interest on ₹2700 at 10% per year for 2 years, compounded every year (in ₹).
  27. 27.What amount will ₹57100 grow to in 1 year at 12% per year compound interest (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹37900 at 20% per year for 2 years (in ₹)?
  29. 29.A scooter is worth ₹29000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  30. 30.What amount will ₹7500 grow to in 2 years at 8% per year compound interest (in ₹)?
  31. 31.A town has 15800 people. The population grows by 4% every year. What will the population be after 1 year?
  32. 32.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
  33. 33.A scooter is worth ₹46600. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  34. 34.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
  35. 35.Find the compound interest on ₹19000 at 4% per year for 1 year, compounded every year (in ₹).
  36. 36.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
  37. 37.What amount will ₹22300 grow to in 1 year at 5% per year compound interest (in ₹)?
  38. 38.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
  39. 39.Find the compound interest on ₹38700 at 20% per year for 1 year, compounded every year (in ₹).
  40. 40.Find the compound interest on ₹37600 at 10% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 25
  2. 29925
  3. 639
  4. 40560
  5. 747
  6. 48668
  7. 64152
  8. 35721
  9. 1875
  10. 100000
  11. 12204
  12. 20577
  13. 4284
  14. 6125
  15. 804
  16. 10625
  17. 48400
  18. 6600
  19. 3822
  20. 3840
  21. 20925
  22. 27904
  23. 4761
  24. 34496
  25. 585
  26. 567
  27. 63952
  28. 1516
  29. 21141
  30. 8748
  31. 16432
  32. 1836
  33. 29824
  34. 80
  35. 760
  36. 55566
  37. 23415
  38. 12501
  39. 7740
  40. 7896

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