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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 996 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.Find the compound interest on ₹7000 at 10% per year for 3 years, compounded every year (in ₹).
  2. 2.What is the difference between the compound interest and the simple interest on ₹47600 at 5% per year for 2 years (in ₹)?
  3. 3.A scooter is worth ₹12500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
  5. 5.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
  6. 6.Find the compound interest on ₹51300 at 4% per year for 1 year, compounded every year (in ₹).
  7. 7.A town has 17600 people. The population grows by 25% every year. What will the population be after 2 years?
  8. 8.What amount will ₹24300 grow to in 1 year at 25% per year compound interest (in ₹)?
  9. 9.Find the compound interest on ₹49400 at 4% per year for 1 year, compounded every year (in ₹).
  10. 10.What amount will ₹5000 grow to in 3 years at 10% per year compound interest (in ₹)?
  11. 11.A scooter is worth ₹27200. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  12. 12.Find the compound interest on ₹2400 at 10% per year for 1 year, compounded every year (in ₹).
  13. 13.Find the compound interest on ₹12600 at 4% per year for 1 year, compounded every year (in ₹).
  14. 14.What is the difference between the compound interest and the simple interest on ₹7600 at 25% per year for 2 years (in ₹)?
  15. 15.Find the compound interest on ₹40000 at 8% per year for 2 years, compounded every year (in ₹).
  16. 16.Find the compound interest on ₹42000 at 10% per year for 1 year, compounded every year (in ₹).
  17. 17.What is the difference between the compound interest and the simple interest on ₹5300 at 10% per year for 2 years (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹4400 at 5% per year for 2 years (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹36900 at 10% per year for 2 years (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹50000 at 5% per year for 2 years (in ₹)?
  21. 21.Find the compound interest on ₹27700 at 4% per year for 1 year, compounded every year (in ₹).
  22. 22.What amount will ₹50000 grow to in 2 years at 8% per year compound interest (in ₹)?
  23. 23.What amount will ₹8400 grow to in 1 year at 25% per year compound interest (in ₹)?
  24. 24.A scooter is worth ₹6400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  25. 25.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  26. 26.What is the difference between the compound interest and the simple interest on ₹59600 at 25% per year for 2 years (in ₹)?
  27. 27.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  28. 28.Find the compound interest on ₹19800 at 8% per year for 1 year, compounded every year (in ₹).
  29. 29.A town has 15000 people. The population grows by 12% every year. What will the population be after 2 years?
  30. 30.Find the compound interest on ₹59500 at 5% per year for 1 year, compounded every year (in ₹).
  31. 31.Find the compound interest on ₹55600 at 15% per year for 2 years, compounded every year (in ₹).
  32. 32.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
  33. 33.Find the compound interest on ₹9600 at 10% per year for 1 year, compounded every year (in ₹).
  34. 34.A town has 12800 people. The population grows by 25% every year. What will the population be after 3 years?
  35. 35.A scooter is worth ₹33900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  36. 36.What amount will ₹55000 grow to in 2 years at 4% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹35600 at 5% per year for 1 year, compounded every year (in ₹).
  38. 38.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹33200 at 10% per year for 2 years (in ₹)?
  40. 40.Find the compound interest on ₹9600 at 5% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 2317
  2. 119
  3. 11520
  4. 44
  5. 9261
  6. 2052
  7. 27500
  8. 30375
  9. 1976
  10. 6655
  11. 23936
  12. 240
  13. 504
  14. 475
  15. 6656
  16. 4200
  17. 53
  18. 11
  19. 369
  20. 125
  21. 1108
  22. 58320
  23. 10500
  24. 2700
  25. 2522
  26. 3725
  27. 48013
  28. 1584
  29. 18816
  30. 2975
  31. 17931
  32. 828
  33. 960
  34. 25000
  35. 32544
  36. 59488
  37. 1780
  38. 28
  39. 332
  40. 480

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