← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 997 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹12800 grow to in 3 years at 25% per year compound interest (in ₹)?
  2. 2.A scooter is worth ₹7600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  3. 3.Find the compound interest on ₹5900 at 10% per year for 1 year, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹52400 at 10% per year for 2 years (in ₹)?
  5. 5.A scooter is worth ₹54000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹14000 at 5% per year for 2 years (in ₹)?
  7. 7.A town has 40600 people. The population grows by 20% every year. What will the population be after 2 years?
  8. 8.What amount will ₹35000 grow to in 2 years at 12% per year compound interest (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹10800 at 5% per year for 2 years (in ₹)?
  10. 10.What amount will ₹5600 grow to in 2 years at 25% per year compound interest (in ₹)?
  11. 11.Find the compound interest on ₹30000 at 8% per year for 2 years, compounded every year (in ₹).
  12. 12.A scooter is worth ₹60000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  13. 13.What amount will ₹2500 grow to in 2 years at 12% per year compound interest (in ₹)?
  14. 14.Find the compound interest on ₹31600 at 4% per year for 1 year, compounded every year (in ₹).
  15. 15.What is the difference between the compound interest and the simple interest on ₹18000 at 5% per year for 2 years (in ₹)?
  16. 16.Find the compound interest on ₹55500 at 20% per year for 3 years, compounded every year (in ₹).
  17. 17.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
  18. 18.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
  19. 19.What amount will ₹59000 grow to in 1 year at 8% per year compound interest (in ₹)?
  20. 20.Find the compound interest on ₹37600 at 20% per year for 2 years, compounded every year (in ₹).
  21. 21.Find the compound interest on ₹25000 at 4% per year for 2 years, compounded every year (in ₹).
  22. 22.A town has 40000 people. The population grows by 15% every year. What will the population be after 3 years?
  23. 23.What is the difference between the compound interest and the simple interest on ₹2300 at 20% per year for 2 years (in ₹)?
  24. 24.Find the compound interest on ₹14200 at 20% per year for 2 years, compounded every year (in ₹).
  25. 25.What amount will ₹41000 grow to in 3 years at 20% per year compound interest (in ₹)?
  26. 26.Find the compound interest on ₹55200 at 4% per year for 1 year, compounded every year (in ₹).
  27. 27.Find the compound interest on ₹41600 at 8% per year for 1 year, compounded every year (in ₹).
  28. 28.What is the difference between the compound interest and the simple interest on ₹17200 at 15% per year for 2 years (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹42600 at 10% per year for 2 years (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹25900 at 10% per year for 2 years (in ₹)?
  31. 31.Find the compound interest on ₹19700 at 15% per year for 1 year, compounded every year (in ₹).
  32. 32.Find the compound interest on ₹40000 at 4% per year for 2 years, compounded every year (in ₹).
  33. 33.A scooter is worth ₹22500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  34. 34.A town has 51700 people. The population grows by 20% every year. What will the population be after 2 years?
  35. 35.What amount will ₹7500 grow to in 2 years at 4% per year compound interest (in ₹)?
  36. 36.What amount will ₹45100 grow to in 2 years at 20% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  38. 38.A scooter is worth ₹48100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  39. 39.Find the compound interest on ₹59300 at 12% per year for 1 year, compounded every year (in ₹).
  40. 40.What amount will ₹49600 grow to in 1 year at 8% per year compound interest (in ₹)?

Answer key

  1. 25000
  2. 6460
  3. 590
  4. 524
  5. 39366
  6. 35
  7. 58464
  8. 43904
  9. 27
  10. 8750
  11. 4992
  12. 55296
  13. 3136
  14. 1264
  15. 45
  16. 40404
  17. 12167
  18. 18522
  19. 63720
  20. 16544
  21. 2040
  22. 60835
  23. 92
  24. 6248
  25. 70848
  26. 2208
  27. 3328
  28. 387
  29. 426
  30. 259
  31. 2955
  32. 3264
  33. 19044
  34. 74448
  35. 8112
  36. 64944
  37. 2522
  38. 43290
  39. 7116
  40. 53568

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets