Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 998 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹29000 at 20% per year for 1 year, compounded every year (in ₹).
2. 2.A town has 29000 people. The population grows by 10% every year. What will the population be after 3 years?
3. 3.A scooter is worth ₹52500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
4. 4.Find the compound interest on ₹20000 at 10% per year for 3 years, compounded every year (in ₹).
5. 5.A town has 20800 people. The population grows by 20% every year. What will the population be after 2 years?
6. 6.Find the compound interest on ₹42500 at 12% per year for 2 years, compounded every year (in ₹).
7. 7.Find the compound interest on ₹49400 at 5% per year for 1 year, compounded every year (in ₹).
8. 8.Find the compound interest on ₹43000 at 10% per year for 3 years, compounded every year (in ₹).
9. 9.A scooter is worth ₹41600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹24400 at 25% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
12. 12.What amount will ₹24200 grow to in 2 years at 20% per year compound interest (in ₹)?
13. 13.A town has 16500 people. The population grows by 10% every year. What will the population be after 1 year?
14. 14.What is the difference between the compound interest and the simple interest on ₹57600 at 25% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
16. 16.A scooter is worth ₹31200. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
17. 17.What amount will ₹27800 grow to in 2 years at 10% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹6000 at 10% per year for 1 year, compounded every year (in ₹).
19. 19.What amount will ₹8400 grow to in 2 years at 5% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹2700 at 25% per year for 1 year, compounded every year (in ₹).
22. 22.Find the compound interest on ₹38600 at 15% per year for 1 year, compounded every year (in ₹).
23. 23.A town has 29100 people. The population grows by 10% every year. What will the population be after 1 year?
24. 24.A scooter is worth ₹12000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
25. 25.Find the compound interest on ₹30600 at 8% per year for 1 year, compounded every year (in ₹).
26. 26.A town has 13100 people. The population grows by 12% every year. What will the population be after 1 year?
27. 27.A town has 40000 people. The population grows by 25% every year. What will the population be after 3 years?
28. 28.A scooter is worth ₹5900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
29. 29.A town has 21700 people. The population grows by 8% every year. What will the population be after 1 year?
30. 30.What amount will ₹2500 grow to in 2 years at 4% per year compound interest (in ₹)?
31. 31.What amount will ₹54200 grow to in 1 year at 10% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹40000 at 12% per year for 2 years, compounded every year (in ₹).
33. 33.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
34. 34.Find the compound interest on ₹44600 at 20% per year for 2 years, compounded every year (in ₹).
35. 35.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
36. 36.Find the compound interest on ₹38000 at 10% per year for 3 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹5000 at 20% per year for 3 years, compounded every year (in ₹).
38. 38.Find the compound interest on ₹9000 at 10% per year for 3 years, compounded every year (in ₹).
39. 39.Find the compound interest on ₹37500 at 12% per year for 2 years, compounded every year (in ₹).
40. 40.Find the compound interest on ₹23700 at 12% per year for 1 year, compounded every year (in ₹).

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