Factorising Quadratics Worksheet

Vedic maths trick 35: Factorising quadratics · Set 129 · 40 sums

The trick (Anurupyena): x² + bx + c: two numbers that multiply to c and add up to b → (x + one)(x + other). ax² + bx + c: multiply a × c; find two numbers that multiply to that and add up to b; split the middle term with them. Group the four terms in pairs and take out the common bracket. Check by multiplying back.

NameDateTime takenScore ___ / 40

1.x² + 3x + 2 =
2.2x² − 23x + 56 =
3.2x² + 19x + 45 =
4.x² + 9x + 18 =
5.x² − 8x + 7 =
6.x² + 7x + 12 =
7.3x² − 22x − 16 =
8.x² + 8x − 9 =
9.x² − 3x − 10 =
10.x² + 15x + 54 =
11.x² + 3x + 2 =
12.x² − 10x + 16 =
13.x² + 15x + 56 =
14.x² − 10x + 24 =
15.x² + 5x − 24 =
16.x² − 3x + 2 =
17.x² − 6x − 7 =
18.x² − 11x + 28 =
19.x² + x − 42 =
20.2x² + x − 45 =
21.x² − 36 =
22.x² − 4x − 32 =
23.x² − 9x + 20 =
24.x² + 19x + 90 =
25.x² + x − 72 =
26.2x² − 3x − 2 =
27.x² + 12x + 32 =
28.x² + 3x + 2 =
29.x² − 13x + 36 =
30.3x² + 13x + 12 =
31.x² + 6x − 7 =
32.3x² + 8x − 3 =
33.3x² + 31x + 36 =
34.3x² − 25x + 50 =
35.2x² + 23x + 45 =
36.x² − x − 20 =
37.x² − 6x + 8 =
38.x² + x − 72 =
39.2x² − x − 36 =
40.3x² − 19x + 20 =

Answer key

(x + 1)(x + 2)
(2x − 7)(x − 8)
(2x + 9)(x + 5)
(x + 6)(x + 3)
(x − 7)(x − 1)
(x + 3)(x + 4)
(3x + 2)(x − 8)
(x + 9)(x − 1)
(x − 5)(x + 2)
(x + 9)(x + 6)
(x + 1)(x + 2)
(x − 2)(x − 8)
(x + 7)(x + 8)
(x − 6)(x − 4)
(x + 8)(x − 3)
(x − 2)(x − 1)
(x + 1)(x − 7)
(x − 7)(x − 4)
(x + 7)(x − 6)
(2x − 9)(x + 5)
(x − 6)(x + 6)
(x + 4)(x − 8)
(x − 4)(x − 5)
(x + 9)(x + 10)
(x − 8)(x + 9)
(2x + 1)(x − 2)
(x + 4)(x + 8)
(x + 1)(x + 2)
(x − 4)(x − 9)
(3x + 4)(x + 3)
(x + 7)(x − 1)
(3x − 1)(x + 3)
(3x + 4)(x + 9)
(3x − 10)(x − 5)
(2x + 5)(x + 9)
(x − 5)(x + 4)
(x − 2)(x − 4)
(x + 9)(x − 8)
(2x − 9)(x + 4)
(3x − 4)(x − 5)

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