Factorising Quadratics Worksheet

Vedic maths trick 35: Factorising quadratics · Set 67 · 40 sums

The trick (Anurupyena): x² + bx + c: two numbers that multiply to c and add up to b → (x + one)(x + other). ax² + bx + c: multiply a × c; find two numbers that multiply to that and add up to b; split the middle term with them. Group the four terms in pairs and take out the common bracket. Check by multiplying back.

NameDateTime takenScore ___ / 40

1.x² + 11x + 28 =
2.x² − 1 =
3.x² + 7x + 10 =
4.x² + 9x + 20 =
5.x² − 11x + 30 =
6.2x² + 11x − 40 =
7.x² − 10x + 16 =
8.x² + 12x + 27 =
9.x² − 9 =
10.x² − 3x + 2 =
11.x² − 8x + 15 =
12.x² − 11x + 24 =
13.3x² + 25x − 18 =
14.x² − 7x − 8 =
15.x² + x − 2 =
16.3x² + 17x + 10 =
17.x² − 1 =
18.x² + 4x − 32 =
19.x² − 11x + 30 =
20.x² − 3x − 28 =
21.x² + 6x + 5 =
22.3x² + 22x + 24 =
23.x² + 5x − 6 =
24.2x² + 21x + 40 =
25.x² − 9 =
26.x² − 5x + 6 =
27.x² − 16x + 63 =
28.2x² − 19x + 24 =
29.x² − 4x − 5 =
30.x² − 9x + 8 =
31.x² − 5x − 6 =
32.x² + 5x + 4 =
33.3x² − 28x + 32 =
34.x² + 2x − 35 =
35.2x² − 15x + 7 =
36.2x² + 25x + 72 =
37.x² + x − 2 =
38.x² − 4x − 45 =
39.x² − 9x + 18 =
40.x² − 7x − 18 =

Answer key

(x + 7)(x + 4)
(x + 1)(x − 1)
(x + 5)(x + 2)
(x + 4)(x + 5)
(x − 6)(x − 5)
(2x − 5)(x + 8)
(x − 2)(x − 8)
(x + 9)(x + 3)
(x + 3)(x − 3)
(x − 2)(x − 1)
(x − 3)(x − 5)
(x − 3)(x − 8)
(3x − 2)(x + 9)
(x + 1)(x − 8)
(x − 1)(x + 2)
(3x + 2)(x + 5)
(x − 1)(x + 1)
(x + 8)(x − 4)
(x − 6)(x − 5)
(x + 4)(x − 7)
(x + 5)(x + 1)
(3x + 4)(x + 6)
(x + 6)(x − 1)
(2x + 5)(x + 8)
(x + 3)(x − 3)
(x − 3)(x − 2)
(x − 9)(x − 7)
(2x − 3)(x − 8)
(x + 1)(x − 5)
(x − 8)(x − 1)
(x + 1)(x − 6)
(x + 1)(x + 4)
(3x − 4)(x − 8)
(x − 5)(x + 7)
(2x − 1)(x − 7)
(2x + 9)(x + 8)
(x − 1)(x + 2)
(x − 9)(x + 5)
(x − 6)(x − 3)
(x − 9)(x + 2)

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