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Recurring Decimals Worksheet

Vedic maths trick 32: Recurring decimals (1/19, 3/29…) · Set 10 · 40 sums
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The trick (Ekadhikena Purvena): Denominator ending in 9: find the Ekadhika — one more than the digits before the 9 (19 → 2, 29 → 3, 39 → 4, 59 → 6). Start: the top number ÷ Ekadhika gives the first decimal digit and a remainder. Every next digit: put the remainder in front of the last digit and divide by the Ekadhika again.

NameDateTime takenScore ___ / 40
  1. 1.8/19 =
  2. 2.7/29 =
  3. 3.8/39 =
  4. 4.4/19 =
  5. 5.9/49 =
  6. 6.9/19 =
  7. 7.6/29 =
  8. 8.5/49 =
  9. 9.1/49 =
  10. 10.5/59 =
  11. 11.4/49 =
  12. 12.4/59 =
  13. 13.9/19 =
  14. 14.4/19 =
  15. 15.6/19 =
  16. 16.8/19 =
  17. 17.9/49 =
  18. 18.6/59 =
  19. 19.2/19 =
  20. 20.4/49 =
  21. 21.8/59 =
  22. 22.5/19 =
  23. 23.3/19 =
  24. 24.3/49 =
  25. 25.6/29 =
  26. 26.6/19 =
  27. 27.1/39 =
  28. 28.2/29 =
  29. 29.8/49 =
  30. 30.9/29 =
  31. 31.2/59 =
  32. 32.9/29 =
  33. 33.6/19 =
  34. 34.3/29 =
  35. 35.4/39 =
  36. 36.2/19 =
  37. 37.9/59 =
  38. 38.3/39 =
  39. 39.2/29 =
  40. 40.3/29 =

Answer key

  1. 0.421052
  2. 0.241379
  3. 0.205128
  4. 0.210526
  5. 0.183673
  6. 0.473684
  7. 0.206896
  8. 0.102040
  9. 0.020408
  10. 0.084745
  11. 0.081632
  12. 0.067796
  13. 0.473684
  14. 0.210526
  15. 0.315789
  16. 0.421052
  17. 0.183673
  18. 0.101694
  19. 0.105263
  20. 0.081632
  21. 0.135593
  22. 0.263157
  23. 0.157894
  24. 0.061224
  25. 0.206896
  26. 0.315789
  27. 0.025641
  28. 0.068965
  29. 0.163265
  30. 0.310344
  31. 0.033898
  32. 0.310344
  33. 0.315789
  34. 0.103448
  35. 0.102564
  36. 0.105263
  37. 0.152542
  38. 0.076923
  39. 0.068965
  40. 0.103448

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