Vedic maths · trick 32 of 36 · free

Recurring decimals (1/19, 3/29…) — Vedic maths trick

1/19 has 18 repeating decimal digits — long division takes ages. For a denominator ending in 9, Vedic maths divides by just one small number: one more than the digit before the 9.

The trick

Ekadhikena Purvena — “by one more than the one before”

  1. Denominator ending in 9: find the Ekadhika — one more than the digits before the 9 (19 → 2, 29 → 3, 39 → 4, 59 → 6).
  2. Start: the top number ÷ Ekadhika gives the first decimal digit and a remainder.
  3. Every next digit: put the remainder in front of the last digit and divide by the Ekadhika again.

Use it for: Fractions like 1/19, 7/29, 4/39, 2/49, 5/59 — and amazing friends with an 18-digit repeating pattern.

Worked example: 1/19 = 0.052631

  1. 19 → divide by 2.
  2. 1 ÷ 2 = 0 rem 1 → 0. Remainder 1 in front of 0 → 10 ÷ 2 = 5 rem 0 → 5.
  3. 5 ÷ 2 = 2 rem 1 → 2. 12 ÷ 2 = 6 → 6. 6 ÷ 2 = 3 → 3. 3 ÷ 2 = 1 rem 1 → 1.
  4. Answer (6 places): 0.052631…

Check: 19 × 0.052631 = 0.999989, just under 1 ✓

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🏁 Trick 32 test

20 sums. Check each answer, then go to the next one. Get 16 or more right to pass.

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🖨️ Recurring Decimals Worksheet

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