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Recurring Decimals Worksheet

Vedic maths trick 32: Recurring decimals (1/19, 3/29…) · Set 210 · 40 sums
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The trick (Ekadhikena Purvena): Denominator ending in 9: find the Ekadhika — one more than the digits before the 9 (19 → 2, 29 → 3, 39 → 4, 59 → 6). Start: the top number ÷ Ekadhika gives the first decimal digit and a remainder. Every next digit: put the remainder in front of the last digit and divide by the Ekadhika again.

NameDateTime takenScore ___ / 40
  1. 1.2/39 =
  2. 2.7/29 =
  3. 3.1/29 =
  4. 4.6/49 =
  5. 5.6/59 =
  6. 6.5/19 =
  7. 7.1/59 =
  8. 8.3/29 =
  9. 9.2/49 =
  10. 10.3/39 =
  11. 11.6/19 =
  12. 12.9/59 =
  13. 13.9/19 =
  14. 14.3/39 =
  15. 15.1/49 =
  16. 16.3/29 =
  17. 17.6/59 =
  18. 18.7/19 =
  19. 19.4/29 =
  20. 20.8/49 =
  21. 21.2/49 =
  22. 22.5/19 =
  23. 23.2/49 =
  24. 24.5/19 =
  25. 25.2/49 =
  26. 26.9/39 =
  27. 27.4/49 =
  28. 28.1/39 =
  29. 29.7/29 =
  30. 30.1/19 =
  31. 31.7/19 =
  32. 32.1/29 =
  33. 33.2/49 =
  34. 34.6/19 =
  35. 35.9/19 =
  36. 36.4/39 =
  37. 37.1/29 =
  38. 38.9/49 =
  39. 39.2/49 =
  40. 40.4/19 =

Answer key

  1. 0.051282
  2. 0.241379
  3. 0.034482
  4. 0.122448
  5. 0.101694
  6. 0.263157
  7. 0.016949
  8. 0.103448
  9. 0.040816
  10. 0.076923
  11. 0.315789
  12. 0.152542
  13. 0.473684
  14. 0.076923
  15. 0.020408
  16. 0.103448
  17. 0.101694
  18. 0.368421
  19. 0.137931
  20. 0.163265
  21. 0.040816
  22. 0.263157
  23. 0.040816
  24. 0.263157
  25. 0.040816
  26. 0.230769
  27. 0.081632
  28. 0.025641
  29. 0.241379
  30. 0.052631
  31. 0.368421
  32. 0.034482
  33. 0.040816
  34. 0.315789
  35. 0.473684
  36. 0.102564
  37. 0.034482
  38. 0.183673
  39. 0.040816
  40. 0.210526

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