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Recurring Decimals Worksheet

Vedic maths trick 32: Recurring decimals (1/19, 3/29…) · Set 23 · 40 sums
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The trick (Ekadhikena Purvena): Denominator ending in 9: find the Ekadhika — one more than the digits before the 9 (19 → 2, 29 → 3, 39 → 4, 59 → 6). Start: the top number ÷ Ekadhika gives the first decimal digit and a remainder. Every next digit: put the remainder in front of the last digit and divide by the Ekadhika again.

NameDateTime takenScore ___ / 40
  1. 1.8/19 =
  2. 2.7/19 =
  3. 3.9/19 =
  4. 4.8/49 =
  5. 5.7/39 =
  6. 6.5/19 =
  7. 7.4/59 =
  8. 8.2/39 =
  9. 9.5/29 =
  10. 10.1/49 =
  11. 11.8/39 =
  12. 12.2/39 =
  13. 13.1/49 =
  14. 14.8/19 =
  15. 15.9/29 =
  16. 16.8/59 =
  17. 17.2/59 =
  18. 18.7/19 =
  19. 19.1/49 =
  20. 20.3/29 =
  21. 21.1/49 =
  22. 22.6/39 =
  23. 23.8/19 =
  24. 24.5/49 =
  25. 25.3/19 =
  26. 26.3/19 =
  27. 27.2/39 =
  28. 28.1/29 =
  29. 29.8/29 =
  30. 30.1/49 =
  31. 31.7/39 =
  32. 32.2/19 =
  33. 33.3/49 =
  34. 34.4/19 =
  35. 35.3/59 =
  36. 36.3/49 =
  37. 37.8/49 =
  38. 38.1/19 =
  39. 39.8/29 =
  40. 40.2/29 =

Answer key

  1. 0.421052
  2. 0.368421
  3. 0.473684
  4. 0.163265
  5. 0.179487
  6. 0.263157
  7. 0.067796
  8. 0.051282
  9. 0.172413
  10. 0.020408
  11. 0.205128
  12. 0.051282
  13. 0.020408
  14. 0.421052
  15. 0.310344
  16. 0.135593
  17. 0.033898
  18. 0.368421
  19. 0.020408
  20. 0.103448
  21. 0.020408
  22. 0.153846
  23. 0.421052
  24. 0.102040
  25. 0.157894
  26. 0.157894
  27. 0.051282
  28. 0.034482
  29. 0.275862
  30. 0.020408
  31. 0.179487
  32. 0.105263
  33. 0.061224
  34. 0.210526
  35. 0.050847
  36. 0.061224
  37. 0.163265
  38. 0.052631
  39. 0.275862
  40. 0.068965

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