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Recurring Decimals Worksheet

Vedic maths trick 32: Recurring decimals (1/19, 3/29…) · Set 241 · 40 sums
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The trick (Ekadhikena Purvena): Denominator ending in 9: find the Ekadhika — one more than the digits before the 9 (19 → 2, 29 → 3, 39 → 4, 59 → 6). Start: the top number ÷ Ekadhika gives the first decimal digit and a remainder. Every next digit: put the remainder in front of the last digit and divide by the Ekadhika again.

NameDateTime takenScore ___ / 40
  1. 1.3/49 =
  2. 2.4/49 =
  3. 3.4/59 =
  4. 4.1/19 =
  5. 5.9/29 =
  6. 6.9/49 =
  7. 7.5/59 =
  8. 8.3/29 =
  9. 9.9/19 =
  10. 10.8/29 =
  11. 11.6/29 =
  12. 12.9/19 =
  13. 13.1/19 =
  14. 14.8/59 =
  15. 15.9/39 =
  16. 16.8/19 =
  17. 17.1/39 =
  18. 18.9/19 =
  19. 19.1/59 =
  20. 20.9/49 =
  21. 21.1/59 =
  22. 22.9/29 =
  23. 23.1/29 =
  24. 24.8/59 =
  25. 25.8/19 =
  26. 26.4/19 =
  27. 27.4/59 =
  28. 28.9/59 =
  29. 29.7/29 =
  30. 30.2/49 =
  31. 31.6/29 =
  32. 32.7/29 =
  33. 33.8/59 =
  34. 34.4/49 =
  35. 35.6/39 =
  36. 36.7/49 =
  37. 37.6/19 =
  38. 38.2/59 =
  39. 39.5/29 =
  40. 40.1/39 =

Answer key

  1. 0.061224
  2. 0.081632
  3. 0.067796
  4. 0.052631
  5. 0.310344
  6. 0.183673
  7. 0.084745
  8. 0.103448
  9. 0.473684
  10. 0.275862
  11. 0.206896
  12. 0.473684
  13. 0.052631
  14. 0.135593
  15. 0.230769
  16. 0.421052
  17. 0.025641
  18. 0.473684
  19. 0.016949
  20. 0.183673
  21. 0.016949
  22. 0.310344
  23. 0.034482
  24. 0.135593
  25. 0.421052
  26. 0.210526
  27. 0.067796
  28. 0.152542
  29. 0.241379
  30. 0.040816
  31. 0.206896
  32. 0.241379
  33. 0.135593
  34. 0.081632
  35. 0.153846
  36. 0.142857
  37. 0.315789
  38. 0.033898
  39. 0.172413
  40. 0.025641

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