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Recurring Decimals Worksheet

Vedic maths trick 32: Recurring decimals (1/19, 3/29…) · Set 313 · 40 sums
TalentJR

The trick (Ekadhikena Purvena): Denominator ending in 9: find the Ekadhika — one more than the digits before the 9 (19 → 2, 29 → 3, 39 → 4, 59 → 6). Start: the top number ÷ Ekadhika gives the first decimal digit and a remainder. Every next digit: put the remainder in front of the last digit and divide by the Ekadhika again.

NameDateTime takenScore ___ / 40
  1. 1.6/59 =
  2. 2.4/39 =
  3. 3.9/19 =
  4. 4.9/49 =
  5. 5.1/19 =
  6. 6.8/59 =
  7. 7.8/19 =
  8. 8.3/29 =
  9. 9.3/39 =
  10. 10.3/49 =
  11. 11.4/59 =
  12. 12.3/19 =
  13. 13.1/29 =
  14. 14.4/39 =
  15. 15.3/49 =
  16. 16.8/19 =
  17. 17.4/39 =
  18. 18.9/39 =
  19. 19.9/19 =
  20. 20.8/59 =
  21. 21.7/19 =
  22. 22.7/19 =
  23. 23.5/59 =
  24. 24.9/19 =
  25. 25.5/29 =
  26. 26.8/59 =
  27. 27.5/19 =
  28. 28.7/19 =
  29. 29.6/39 =
  30. 30.3/49 =
  31. 31.8/49 =
  32. 32.9/39 =
  33. 33.2/49 =
  34. 34.3/49 =
  35. 35.8/19 =
  36. 36.1/19 =
  37. 37.8/19 =
  38. 38.9/29 =
  39. 39.1/59 =
  40. 40.4/49 =

Answer key

  1. 0.101694
  2. 0.102564
  3. 0.473684
  4. 0.183673
  5. 0.052631
  6. 0.135593
  7. 0.421052
  8. 0.103448
  9. 0.076923
  10. 0.061224
  11. 0.067796
  12. 0.157894
  13. 0.034482
  14. 0.102564
  15. 0.061224
  16. 0.421052
  17. 0.102564
  18. 0.230769
  19. 0.473684
  20. 0.135593
  21. 0.368421
  22. 0.368421
  23. 0.084745
  24. 0.473684
  25. 0.172413
  26. 0.135593
  27. 0.263157
  28. 0.368421
  29. 0.153846
  30. 0.061224
  31. 0.163265
  32. 0.230769
  33. 0.040816
  34. 0.061224
  35. 0.421052
  36. 0.052631
  37. 0.421052
  38. 0.310344
  39. 0.016949
  40. 0.081632

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