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Recurring Decimals Worksheet

Vedic maths trick 32: Recurring decimals (1/19, 3/29…) · Set 471 · 40 sums
TalentJR

The trick (Ekadhikena Purvena): Denominator ending in 9: find the Ekadhika — one more than the digits before the 9 (19 → 2, 29 → 3, 39 → 4, 59 → 6). Start: the top number ÷ Ekadhika gives the first decimal digit and a remainder. Every next digit: put the remainder in front of the last digit and divide by the Ekadhika again.

NameDateTime takenScore ___ / 40
  1. 1.3/19 =
  2. 2.2/29 =
  3. 3.3/19 =
  4. 4.9/19 =
  5. 5.6/29 =
  6. 6.2/19 =
  7. 7.4/29 =
  8. 8.1/49 =
  9. 9.2/29 =
  10. 10.1/49 =
  11. 11.4/39 =
  12. 12.8/19 =
  13. 13.8/19 =
  14. 14.9/29 =
  15. 15.5/49 =
  16. 16.1/59 =
  17. 17.1/29 =
  18. 18.2/29 =
  19. 19.8/19 =
  20. 20.5/59 =
  21. 21.3/49 =
  22. 22.6/49 =
  23. 23.8/49 =
  24. 24.4/19 =
  25. 25.9/59 =
  26. 26.6/49 =
  27. 27.2/59 =
  28. 28.3/19 =
  29. 29.5/19 =
  30. 30.6/29 =
  31. 31.2/19 =
  32. 32.1/49 =
  33. 33.6/49 =
  34. 34.9/19 =
  35. 35.6/49 =
  36. 36.5/59 =
  37. 37.1/19 =
  38. 38.1/19 =
  39. 39.9/19 =
  40. 40.6/49 =

Answer key

  1. 0.157894
  2. 0.068965
  3. 0.157894
  4. 0.473684
  5. 0.206896
  6. 0.105263
  7. 0.137931
  8. 0.020408
  9. 0.068965
  10. 0.020408
  11. 0.102564
  12. 0.421052
  13. 0.421052
  14. 0.310344
  15. 0.102040
  16. 0.016949
  17. 0.034482
  18. 0.068965
  19. 0.421052
  20. 0.084745
  21. 0.061224
  22. 0.122448
  23. 0.163265
  24. 0.210526
  25. 0.152542
  26. 0.122448
  27. 0.033898
  28. 0.157894
  29. 0.263157
  30. 0.206896
  31. 0.105263
  32. 0.020408
  33. 0.122448
  34. 0.473684
  35. 0.122448
  36. 0.084745
  37. 0.052631
  38. 0.052631
  39. 0.473684
  40. 0.122448

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