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Recurring Decimals Worksheet

Vedic maths trick 32: Recurring decimals (1/19, 3/29…) · Set 560 · 40 sums
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The trick (Ekadhikena Purvena): Denominator ending in 9: find the Ekadhika — one more than the digits before the 9 (19 → 2, 29 → 3, 39 → 4, 59 → 6). Start: the top number ÷ Ekadhika gives the first decimal digit and a remainder. Every next digit: put the remainder in front of the last digit and divide by the Ekadhika again.

NameDateTime takenScore ___ / 40
  1. 1.8/29 =
  2. 2.9/59 =
  3. 3.6/19 =
  4. 4.7/59 =
  5. 5.9/19 =
  6. 6.6/19 =
  7. 7.1/39 =
  8. 8.3/29 =
  9. 9.5/29 =
  10. 10.8/59 =
  11. 11.9/29 =
  12. 12.1/59 =
  13. 13.4/49 =
  14. 14.1/49 =
  15. 15.1/59 =
  16. 16.9/59 =
  17. 17.8/59 =
  18. 18.9/49 =
  19. 19.6/49 =
  20. 20.2/19 =
  21. 21.3/19 =
  22. 22.7/49 =
  23. 23.6/39 =
  24. 24.8/29 =
  25. 25.8/29 =
  26. 26.8/49 =
  27. 27.3/39 =
  28. 28.7/29 =
  29. 29.4/59 =
  30. 30.9/19 =
  31. 31.5/19 =
  32. 32.1/39 =
  33. 33.5/39 =
  34. 34.2/49 =
  35. 35.3/49 =
  36. 36.8/19 =
  37. 37.3/59 =
  38. 38.9/19 =
  39. 39.1/29 =
  40. 40.8/49 =

Answer key

  1. 0.275862
  2. 0.152542
  3. 0.315789
  4. 0.118644
  5. 0.473684
  6. 0.315789
  7. 0.025641
  8. 0.103448
  9. 0.172413
  10. 0.135593
  11. 0.310344
  12. 0.016949
  13. 0.081632
  14. 0.020408
  15. 0.016949
  16. 0.152542
  17. 0.135593
  18. 0.183673
  19. 0.122448
  20. 0.105263
  21. 0.157894
  22. 0.142857
  23. 0.153846
  24. 0.275862
  25. 0.275862
  26. 0.163265
  27. 0.076923
  28. 0.241379
  29. 0.067796
  30. 0.473684
  31. 0.263157
  32. 0.025641
  33. 0.128205
  34. 0.040816
  35. 0.061224
  36. 0.421052
  37. 0.050847
  38. 0.473684
  39. 0.034482
  40. 0.163265

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