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Recurring Decimals Worksheet

Vedic maths trick 32: Recurring decimals (1/19, 3/29…) · Set 650 · 40 sums
TalentJR

The trick (Ekadhikena Purvena): Denominator ending in 9: find the Ekadhika — one more than the digits before the 9 (19 → 2, 29 → 3, 39 → 4, 59 → 6). Start: the top number ÷ Ekadhika gives the first decimal digit and a remainder. Every next digit: put the remainder in front of the last digit and divide by the Ekadhika again.

NameDateTime takenScore ___ / 40
  1. 1.6/59 =
  2. 2.4/39 =
  3. 3.2/59 =
  4. 4.4/59 =
  5. 5.5/19 =
  6. 6.7/29 =
  7. 7.4/59 =
  8. 8.2/29 =
  9. 9.6/29 =
  10. 10.5/19 =
  11. 11.2/49 =
  12. 12.4/29 =
  13. 13.9/19 =
  14. 14.2/39 =
  15. 15.1/29 =
  16. 16.6/29 =
  17. 17.3/49 =
  18. 18.2/19 =
  19. 19.2/49 =
  20. 20.5/49 =
  21. 21.2/59 =
  22. 22.8/59 =
  23. 23.4/29 =
  24. 24.7/59 =
  25. 25.7/49 =
  26. 26.2/29 =
  27. 27.2/29 =
  28. 28.1/29 =
  29. 29.5/29 =
  30. 30.9/29 =
  31. 31.9/19 =
  32. 32.4/29 =
  33. 33.2/19 =
  34. 34.4/59 =
  35. 35.5/49 =
  36. 36.5/19 =
  37. 37.6/59 =
  38. 38.8/39 =
  39. 39.5/29 =
  40. 40.5/19 =

Answer key

  1. 0.101694
  2. 0.102564
  3. 0.033898
  4. 0.067796
  5. 0.263157
  6. 0.241379
  7. 0.067796
  8. 0.068965
  9. 0.206896
  10. 0.263157
  11. 0.040816
  12. 0.137931
  13. 0.473684
  14. 0.051282
  15. 0.034482
  16. 0.206896
  17. 0.061224
  18. 0.105263
  19. 0.040816
  20. 0.102040
  21. 0.033898
  22. 0.135593
  23. 0.137931
  24. 0.118644
  25. 0.142857
  26. 0.068965
  27. 0.068965
  28. 0.034482
  29. 0.172413
  30. 0.310344
  31. 0.473684
  32. 0.137931
  33. 0.105263
  34. 0.067796
  35. 0.102040
  36. 0.263157
  37. 0.101694
  38. 0.205128
  39. 0.172413
  40. 0.263157

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