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Recurring Decimals Worksheet

Vedic maths trick 32: Recurring decimals (1/19, 3/29…) · Set 692 · 40 sums
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The trick (Ekadhikena Purvena): Denominator ending in 9: find the Ekadhika — one more than the digits before the 9 (19 → 2, 29 → 3, 39 → 4, 59 → 6). Start: the top number ÷ Ekadhika gives the first decimal digit and a remainder. Every next digit: put the remainder in front of the last digit and divide by the Ekadhika again.

NameDateTime takenScore ___ / 40
  1. 1.2/19 =
  2. 2.8/29 =
  3. 3.4/49 =
  4. 4.8/19 =
  5. 5.4/49 =
  6. 6.6/49 =
  7. 7.6/29 =
  8. 8.3/29 =
  9. 9.6/29 =
  10. 10.8/19 =
  11. 11.7/49 =
  12. 12.2/29 =
  13. 13.2/29 =
  14. 14.9/29 =
  15. 15.8/19 =
  16. 16.9/29 =
  17. 17.1/29 =
  18. 18.8/29 =
  19. 19.6/19 =
  20. 20.3/49 =
  21. 21.1/59 =
  22. 22.2/49 =
  23. 23.3/19 =
  24. 24.5/19 =
  25. 25.6/49 =
  26. 26.9/19 =
  27. 27.9/19 =
  28. 28.5/49 =
  29. 29.5/19 =
  30. 30.8/39 =
  31. 31.6/59 =
  32. 32.2/39 =
  33. 33.8/59 =
  34. 34.2/49 =
  35. 35.9/19 =
  36. 36.9/19 =
  37. 37.3/29 =
  38. 38.2/49 =
  39. 39.5/49 =
  40. 40.3/49 =

Answer key

  1. 0.105263
  2. 0.275862
  3. 0.081632
  4. 0.421052
  5. 0.081632
  6. 0.122448
  7. 0.206896
  8. 0.103448
  9. 0.206896
  10. 0.421052
  11. 0.142857
  12. 0.068965
  13. 0.068965
  14. 0.310344
  15. 0.421052
  16. 0.310344
  17. 0.034482
  18. 0.275862
  19. 0.315789
  20. 0.061224
  21. 0.016949
  22. 0.040816
  23. 0.157894
  24. 0.263157
  25. 0.122448
  26. 0.473684
  27. 0.473684
  28. 0.102040
  29. 0.263157
  30. 0.205128
  31. 0.101694
  32. 0.051282
  33. 0.135593
  34. 0.040816
  35. 0.473684
  36. 0.473684
  37. 0.103448
  38. 0.040816
  39. 0.102040
  40. 0.061224

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