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Recurring Decimals Worksheet

Vedic maths trick 32: Recurring decimals (1/19, 3/29…) · Set 740 · 40 sums
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The trick (Ekadhikena Purvena): Denominator ending in 9: find the Ekadhika — one more than the digits before the 9 (19 → 2, 29 → 3, 39 → 4, 59 → 6). Start: the top number ÷ Ekadhika gives the first decimal digit and a remainder. Every next digit: put the remainder in front of the last digit and divide by the Ekadhika again.

NameDateTime takenScore ___ / 40
  1. 1.7/39 =
  2. 2.9/39 =
  3. 3.6/19 =
  4. 4.2/49 =
  5. 5.1/19 =
  6. 6.2/49 =
  7. 7.4/19 =
  8. 8.5/49 =
  9. 9.6/49 =
  10. 10.3/49 =
  11. 11.1/29 =
  12. 12.2/19 =
  13. 13.6/49 =
  14. 14.2/19 =
  15. 15.8/29 =
  16. 16.1/39 =
  17. 17.5/19 =
  18. 18.2/49 =
  19. 19.3/59 =
  20. 20.1/29 =
  21. 21.9/59 =
  22. 22.1/19 =
  23. 23.9/59 =
  24. 24.9/19 =
  25. 25.7/19 =
  26. 26.1/39 =
  27. 27.7/39 =
  28. 28.1/29 =
  29. 29.2/19 =
  30. 30.1/29 =
  31. 31.7/19 =
  32. 32.2/29 =
  33. 33.9/59 =
  34. 34.5/19 =
  35. 35.5/29 =
  36. 36.2/39 =
  37. 37.3/49 =
  38. 38.4/59 =
  39. 39.4/49 =
  40. 40.8/19 =

Answer key

  1. 0.179487
  2. 0.230769
  3. 0.315789
  4. 0.040816
  5. 0.052631
  6. 0.040816
  7. 0.210526
  8. 0.102040
  9. 0.122448
  10. 0.061224
  11. 0.034482
  12. 0.105263
  13. 0.122448
  14. 0.105263
  15. 0.275862
  16. 0.025641
  17. 0.263157
  18. 0.040816
  19. 0.050847
  20. 0.034482
  21. 0.152542
  22. 0.052631
  23. 0.152542
  24. 0.473684
  25. 0.368421
  26. 0.025641
  27. 0.179487
  28. 0.034482
  29. 0.105263
  30. 0.034482
  31. 0.368421
  32. 0.068965
  33. 0.152542
  34. 0.263157
  35. 0.172413
  36. 0.051282
  37. 0.061224
  38. 0.067796
  39. 0.081632
  40. 0.421052

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