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Recurring Decimals Worksheet

Vedic maths trick 32: Recurring decimals (1/19, 3/29…) · Set 802 · 40 sums
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The trick (Ekadhikena Purvena): Denominator ending in 9: find the Ekadhika — one more than the digits before the 9 (19 → 2, 29 → 3, 39 → 4, 59 → 6). Start: the top number ÷ Ekadhika gives the first decimal digit and a remainder. Every next digit: put the remainder in front of the last digit and divide by the Ekadhika again.

NameDateTime takenScore ___ / 40
  1. 1.9/19 =
  2. 2.5/49 =
  3. 3.5/39 =
  4. 4.8/59 =
  5. 5.6/29 =
  6. 6.2/39 =
  7. 7.2/49 =
  8. 8.5/39 =
  9. 9.2/59 =
  10. 10.4/19 =
  11. 11.8/29 =
  12. 12.5/29 =
  13. 13.6/19 =
  14. 14.9/59 =
  15. 15.6/29 =
  16. 16.5/19 =
  17. 17.4/19 =
  18. 18.3/39 =
  19. 19.4/29 =
  20. 20.1/29 =
  21. 21.9/59 =
  22. 22.9/49 =
  23. 23.1/29 =
  24. 24.3/19 =
  25. 25.9/39 =
  26. 26.3/59 =
  27. 27.9/19 =
  28. 28.3/59 =
  29. 29.9/39 =
  30. 30.4/19 =
  31. 31.6/19 =
  32. 32.3/49 =
  33. 33.6/39 =
  34. 34.6/39 =
  35. 35.5/39 =
  36. 36.5/49 =
  37. 37.5/49 =
  38. 38.1/19 =
  39. 39.4/19 =
  40. 40.3/29 =

Answer key

  1. 0.473684
  2. 0.102040
  3. 0.128205
  4. 0.135593
  5. 0.206896
  6. 0.051282
  7. 0.040816
  8. 0.128205
  9. 0.033898
  10. 0.210526
  11. 0.275862
  12. 0.172413
  13. 0.315789
  14. 0.152542
  15. 0.206896
  16. 0.263157
  17. 0.210526
  18. 0.076923
  19. 0.137931
  20. 0.034482
  21. 0.152542
  22. 0.183673
  23. 0.034482
  24. 0.157894
  25. 0.230769
  26. 0.050847
  27. 0.473684
  28. 0.050847
  29. 0.230769
  30. 0.210526
  31. 0.315789
  32. 0.061224
  33. 0.153846
  34. 0.153846
  35. 0.128205
  36. 0.102040
  37. 0.102040
  38. 0.052631
  39. 0.210526
  40. 0.103448

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