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Recurring Decimals Worksheet

Vedic maths trick 32: Recurring decimals (1/19, 3/29…) · Set 810 · 40 sums
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The trick (Ekadhikena Purvena): Denominator ending in 9: find the Ekadhika — one more than the digits before the 9 (19 → 2, 29 → 3, 39 → 4, 59 → 6). Start: the top number ÷ Ekadhika gives the first decimal digit and a remainder. Every next digit: put the remainder in front of the last digit and divide by the Ekadhika again.

NameDateTime takenScore ___ / 40
  1. 1.7/19 =
  2. 2.8/39 =
  3. 3.2/29 =
  4. 4.4/19 =
  5. 5.4/59 =
  6. 6.2/59 =
  7. 7.5/19 =
  8. 8.2/19 =
  9. 9.9/59 =
  10. 10.4/39 =
  11. 11.7/49 =
  12. 12.7/49 =
  13. 13.8/49 =
  14. 14.5/59 =
  15. 15.8/19 =
  16. 16.7/19 =
  17. 17.9/19 =
  18. 18.8/29 =
  19. 19.1/49 =
  20. 20.3/19 =
  21. 21.9/59 =
  22. 22.1/59 =
  23. 23.6/19 =
  24. 24.5/49 =
  25. 25.7/49 =
  26. 26.7/19 =
  27. 27.2/29 =
  28. 28.3/39 =
  29. 29.1/49 =
  30. 30.8/49 =
  31. 31.3/39 =
  32. 32.5/19 =
  33. 33.4/59 =
  34. 34.1/59 =
  35. 35.8/19 =
  36. 36.9/39 =
  37. 37.2/29 =
  38. 38.7/49 =
  39. 39.6/19 =
  40. 40.8/39 =

Answer key

  1. 0.368421
  2. 0.205128
  3. 0.068965
  4. 0.210526
  5. 0.067796
  6. 0.033898
  7. 0.263157
  8. 0.105263
  9. 0.152542
  10. 0.102564
  11. 0.142857
  12. 0.142857
  13. 0.163265
  14. 0.084745
  15. 0.421052
  16. 0.368421
  17. 0.473684
  18. 0.275862
  19. 0.020408
  20. 0.157894
  21. 0.152542
  22. 0.016949
  23. 0.315789
  24. 0.102040
  25. 0.142857
  26. 0.368421
  27. 0.068965
  28. 0.076923
  29. 0.020408
  30. 0.163265
  31. 0.076923
  32. 0.263157
  33. 0.067796
  34. 0.016949
  35. 0.421052
  36. 0.230769
  37. 0.068965
  38. 0.142857
  39. 0.315789
  40. 0.205128

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