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Recurring Decimals Worksheet

Vedic maths trick 32: Recurring decimals (1/19, 3/29…) · Set 877 · 40 sums
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The trick (Ekadhikena Purvena): Denominator ending in 9: find the Ekadhika — one more than the digits before the 9 (19 → 2, 29 → 3, 39 → 4, 59 → 6). Start: the top number ÷ Ekadhika gives the first decimal digit and a remainder. Every next digit: put the remainder in front of the last digit and divide by the Ekadhika again.

NameDateTime takenScore ___ / 40
  1. 1.8/39 =
  2. 2.7/29 =
  3. 3.2/49 =
  4. 4.8/59 =
  5. 5.8/39 =
  6. 6.3/59 =
  7. 7.9/49 =
  8. 8.9/29 =
  9. 9.6/39 =
  10. 10.9/29 =
  11. 11.1/39 =
  12. 12.5/29 =
  13. 13.8/59 =
  14. 14.3/59 =
  15. 15.7/19 =
  16. 16.1/39 =
  17. 17.5/29 =
  18. 18.9/39 =
  19. 19.1/59 =
  20. 20.9/49 =
  21. 21.1/39 =
  22. 22.9/29 =
  23. 23.3/29 =
  24. 24.8/59 =
  25. 25.8/19 =
  26. 26.4/39 =
  27. 27.8/19 =
  28. 28.1/29 =
  29. 29.3/59 =
  30. 30.1/49 =
  31. 31.9/29 =
  32. 32.2/49 =
  33. 33.3/49 =
  34. 34.8/49 =
  35. 35.7/19 =
  36. 36.8/39 =
  37. 37.1/19 =
  38. 38.7/19 =
  39. 39.1/29 =
  40. 40.6/39 =

Answer key

  1. 0.205128
  2. 0.241379
  3. 0.040816
  4. 0.135593
  5. 0.205128
  6. 0.050847
  7. 0.183673
  8. 0.310344
  9. 0.153846
  10. 0.310344
  11. 0.025641
  12. 0.172413
  13. 0.135593
  14. 0.050847
  15. 0.368421
  16. 0.025641
  17. 0.172413
  18. 0.230769
  19. 0.016949
  20. 0.183673
  21. 0.025641
  22. 0.310344
  23. 0.103448
  24. 0.135593
  25. 0.421052
  26. 0.102564
  27. 0.421052
  28. 0.034482
  29. 0.050847
  30. 0.020408
  31. 0.310344
  32. 0.040816
  33. 0.061224
  34. 0.163265
  35. 0.368421
  36. 0.205128
  37. 0.052631
  38. 0.368421
  39. 0.034482
  40. 0.153846

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