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Recurring Decimals Worksheet

Vedic maths trick 32: Recurring decimals (1/19, 3/29…) · Set 912 · 40 sums
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The trick (Ekadhikena Purvena): Denominator ending in 9: find the Ekadhika — one more than the digits before the 9 (19 → 2, 29 → 3, 39 → 4, 59 → 6). Start: the top number ÷ Ekadhika gives the first decimal digit and a remainder. Every next digit: put the remainder in front of the last digit and divide by the Ekadhika again.

NameDateTime takenScore ___ / 40
  1. 1.1/39 =
  2. 2.9/49 =
  3. 3.3/29 =
  4. 4.5/19 =
  5. 5.7/19 =
  6. 6.8/29 =
  7. 7.6/19 =
  8. 8.4/19 =
  9. 9.1/29 =
  10. 10.7/49 =
  11. 11.1/19 =
  12. 12.3/49 =
  13. 13.6/19 =
  14. 14.7/19 =
  15. 15.6/19 =
  16. 16.1/49 =
  17. 17.3/59 =
  18. 18.8/19 =
  19. 19.2/19 =
  20. 20.5/49 =
  21. 21.3/19 =
  22. 22.4/19 =
  23. 23.9/29 =
  24. 24.1/39 =
  25. 25.7/49 =
  26. 26.9/29 =
  27. 27.4/49 =
  28. 28.7/19 =
  29. 29.1/49 =
  30. 30.8/29 =
  31. 31.1/39 =
  32. 32.4/59 =
  33. 33.7/19 =
  34. 34.8/59 =
  35. 35.7/49 =
  36. 36.3/49 =
  37. 37.6/39 =
  38. 38.9/59 =
  39. 39.8/19 =
  40. 40.5/29 =

Answer key

  1. 0.025641
  2. 0.183673
  3. 0.103448
  4. 0.263157
  5. 0.368421
  6. 0.275862
  7. 0.315789
  8. 0.210526
  9. 0.034482
  10. 0.142857
  11. 0.052631
  12. 0.061224
  13. 0.315789
  14. 0.368421
  15. 0.315789
  16. 0.020408
  17. 0.050847
  18. 0.421052
  19. 0.105263
  20. 0.102040
  21. 0.157894
  22. 0.210526
  23. 0.310344
  24. 0.025641
  25. 0.142857
  26. 0.310344
  27. 0.081632
  28. 0.368421
  29. 0.020408
  30. 0.275862
  31. 0.025641
  32. 0.067796
  33. 0.368421
  34. 0.135593
  35. 0.142857
  36. 0.061224
  37. 0.153846
  38. 0.152542
  39. 0.421052
  40. 0.172413

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