Introduction to Three Dimensional Geometry – Class 11 Maths Chapter 11 Notes & NCERT PDF
Notes and a simple summary of Chapter 11 of the NCERT Class 11 Mathematics book, with the official chapter PDF, flashcards, an MCQ quiz and an AI tutor for your doubts.
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Chapter 11: Introduction to Three Dimensional Geometry
Introduction
Chapter 11, Introduction to Three Dimensional Geometry, extends the coordinate idea from a plane to space. A point in a plane needs two numbers; a flying bird, a hanging lamp or an aeroplane needs three. The chapter sets up three mutually perpendicular axes, names the planes and octants they create, and derives the distance formula in space. (In the rationalised syllabus the chapter covers sections 11.1–11.4 plus miscellaneous examples.)
Key Concepts & Theorems
11.2 Coordinate Axes and Coordinate Planes
11.3 Coordinates of a Point in Space
From a point P drop perpendiculars to the three coordinate planes. The coordinates (x, y, z) of P are its distances from the YZ-, ZX- and XY-planes respectively, with signs.
Signs in the octants (Table 11.1):
11.4 Distance between Two Points
For P(x₁, y₁, z₁) and Q(x₂, y₂, z₂):
PQ = √[(x₂ − x₁)² + (y₂ − y₁)² + (z₂ − z₁)²]
The distance of P(x, y, z) from the origin is √(x² + y² + z²). This formula lets us test collinearity (PQ + QR = PR), classify triangles (isosceles, right-angled) and identify parallelograms.
Worked Examples
Example 1. If P is (2, 4, 5) in the book's figure, the point F lies in the ZX-plane below it, so its y-coordinate is 0: F = (2, 0, 5).
Example 2 (octants). (−3, 1, 2) has signs (−, +, +) → octant II; (−3, 1, −2) has signs (−, +, −) → octant VI.
Example 3 (distance). P(1, −3, 4), Q(−4, 1, 2): PQ = √(25 + 16 + 4) = √45 = 3√5.
Example 4 (collinearity). P(−2, 3, 5), Q(1, 2, 3), R(7, 0, −1): PQ = √14, QR = √56 = 2√14, PR = √126 = 3√14. Since PQ + QR = PR, the points are collinear.
Example 5 (right triangle test). A(3, 6, 9), B(10, 20, 30), C(25, −41, 5): AB² = 686, BC² = 4571, CA² = 2709. No sum of two squares equals the third (686 + 2709 = 3395 ≠ 4571), so ABC is not a right-angled triangle.
Example 6 (locus). Points P with PA² + PB² = 2k², A(3, 4, 5), B(−1, 3, −7): expanding gives 2x² + 2y² + 2z² − 4x − 14y + 4z = 2k² − 109.
Example 9 (centroid). The centroid of triangle ABC is (1, 1, 1), A = (3, −5, 7) and B = (−1, 7, −6). Using (x₁ + x₂ + x₃)/3 = 1 etc., C = (1, 1, 2).
Formula Sheet
Exam Focus
Exercise 11.1 asks for coordinates of points on axes/planes and octants of given points; Exercise 11.2 asks for distances, collinearity, isosceles/right triangles, parallelograms and loci (e.g. points equidistant from (1, 2, 3) and (3, 2, −1), which simplifies to x − 2z = 0).
Outline — "Show that P, Q, R are collinear": compute PQ, QR, PR in simplest surd form; show the largest equals the sum of the other two.
Outline — "Verify a right-angled triangle": compute the three squared lengths; check whether one equals the sum of the other two (Pythagoras).
Outline — "Name the octant": write the sign pattern of (x, y, z) and match it to Table 11.1.
Key Terms
Common Mistakes
💡 Key Learning Points
- ✓Three mutually perpendicular axes (x, y, z) meeting at the origin define a rectangular Cartesian system in space.
- ✓The XY-, YZ- and ZX-planes divide space into eight octants, each with its own sign pattern (I: +,+,+ to VIII: +,−,−).
- ✓The coordinates (x, y, z) of a point are its distances from the YZ-, ZX- and XY-planes respectively.
- ✓Points on axes and planes have zero coordinates in a fixed pattern, e.g. (x, 0, 0) on the x-axis and (x, y, 0) in the XY-plane.
- ✓PQ = √[(x₂ − x₁)² + (y₂ − y₁)² + (z₂ − z₁)²] is used for collinearity, triangle classification and loci.
👨🏫 Teaching Tips
- →Use the corner of the classroom: two walls and the floor are the three coordinate planes and their edges are the axes.
- →Hold up a box or a matchbox to locate a corner point by moving along x, then y, then z.
- →Give students the octant sign list and play a quick 'name the octant' round with random points.
- →Derive the 3D distance formula by applying Pythagoras twice (floor diagonal, then height).
- →Show that the 2D distance formula is the special case z₁ = z₂.
- →Assign an application: distance of a drone from its launch point given three coordinates.
📋 Assessment Questions
- What are the y- and z-coordinates of a point on the x-axis?
- Name the octants of (4, −2, 3), (4, −2, −5) and (−2, −4, −7).
- Find the distance between (1, −3, 4) and (−4, 1, 2).
- Show that (−2, 3, 5), (1, 2, 3) and (7, 0, −1) are collinear.
- Find the equation of the set of points equidistant from (1, 2, 3) and (3, 2, −1).
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All chapters in Mathematics - Class 11
- 1. Sets
- 2. Relations and Functions
- 3. Trigonometric Functions
- 4. Complex Numbers and Quadratic Equations
- 5. Linear Inequalities
- 6. Permutations and Combinations
- 7. Binomial Theorem
- 8. Sequences and Series
- 9. Straight Lines
- 10. Conic Sections
- 11. Introduction to Three Dimensional Geometry
- 12. Limits and Derivatives
- 13. Statistics
- 14. Probability