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Work, Energy and Power – Class 11 Physics Chapter 5 Notes & NCERT PDF

Class 11PhysicsChapter 5NCERT book: Physics Part I - Class 11

Notes and a simple summary of Chapter 5 of the NCERT Class 11 Physics book, with the official chapter PDF, flashcards, an MCQ quiz and an AI tutor for your doubts.

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Chapter 5: Work, Energy and Power

Introduction

In everyday language "work", "energy" and "power" are used loosely. In physics each has a precise meaning. The chapter first reviews the scalar (dot) product, then defines work, links it to kinetic energy through the work-energy theorem, introduces potential energy and conservation of mechanical energy, and ends with power and collisions.

Key Concepts

5.1.1 The Scalar Product

A·B = A B cos θ — a scalar. It is commutative and distributive; in components A·B = AxBx + AyBy + AzBz. A·B = 0 when the vectors are perpendicular.

5.2 Notions of Work and Kinetic Energy

For constant acceleration, v² − u² = 2 a s; multiplying by m/2 gives ½mv² − ½mu² = F s. The quantity ½ m v² is kinetic energy and F·d is work.

Work-energy theorem: The change in kinetic energy of a particle is equal to the work done on it by the net force.

5.3 Work

W = F·d = F d cos θ. Work is zero if (i) displacement is zero (pushing a wall), (ii) force is zero (a block moving on a frictionless surface), or (iii) force ⟂ displacement (gravity on a body moving horizontally). Work can be positive or negative — friction on a sliding body does negative work. SI unit: joule (1 J = 1 N m); other units: erg (10⁻⁷ J), electron volt (1.6 × 10⁻¹⁹ J), calorie (4.186 J), kilowatt hour (3.6 × 10⁶ J).

5.4 Kinetic Energy

K = ½ m v² — a scalar measure of the work a moving body can do (flowing water turns mills, wind drives windmills). The book's table compares kinetic energies — e.g. a bullet of 50 g at 200 m s⁻¹ has 1000 J.

5.5 Work Done by a Variable Force

W = ∫ F(x) dx from xi to xf — the area under the force–displacement graph.

5.6 Work-Energy Theorem for a Variable Force

Using F = m dv/dt = m v dv/dx, integrating gives Kf − Ki = W — the theorem holds for variable forces too. It is not independent of the second law; it is the second law "integrated" over displacement.

5.7 The Concept of Potential Energy

Potential energy is stored energy of position or configuration. For gravity near the earth, V = m g h. A force is conservative if it can be written as F = −dV/dx, the work it does depends only on initial and final positions (not the path), and work around a closed path is zero. Gravity and spring force are conservative; friction is not.

5.8 Conservation of Mechanical Energy

The total mechanical energy of a system is conserved if the forces doing work on it are conservative.

K + V = constant. A ball released from height H: at the top all energy is m g H, at the ground all is ½mv², so v = √(2gH). If a non-conservative force (friction) also acts, Ki + Vi = Kf + Vf + |work done against friction|.

5.9 Potential Energy of a Spring

Spring force (Hooke's law) F = −k x, k = spring constant. Work stored = ½ k x². An oscillating mass-spring system converts K and V back and forth; at the extreme position energy is all potential, at the mean position all kinetic.

5.10 Power

Power is the time rate of doing work: average P = W/t; instantaneous P = dW/dt = F·v. SI unit watt (1 W = 1 J s⁻¹); 1 horsepower = 746 W. Electricity bills are in kWh (a unit of energy, not power).

5.11 Collisions

Momentum is conserved in all collisions; kinetic energy is conserved only in elastic collisions.

  • Perfectly inelastic: bodies stick together; KE lost.
  • Elastic, 1-D: v₁f = [(m₁ − m₂)/(m₁ + m₂)] v₁i and v₂f = [2m₁/(m₁ + m₂)] v₁i (target at rest). Equal masses exchange velocities.
  • 2-D: conservation of momentum gives two component equations; with elastic, equal masses, the two balls move off at right angles.
  • Worked Examples

  • Cyclist skidding (Ex 5.3). Road force 200 N opposes motion over 10 m: work by road on cycle = −200 × 10 = −2000 J. Work by cycle on road = 0, because the road does not move.
  • Bullet through plywood (Ex 5.4). m = 50 g, u = 200 m s⁻¹ ⇒ Ki = 1000 J. It emerges with 10%, i.e. 100 J ⇒ v = √(2 × 100/0.05) ≈ 63.2 m s⁻¹.
  • Woman pushing a trunk (Ex 5.5). 100 N over the first 10 m, then decreasing linearly to 50 N over the next 10 m. Work = area = 100 × 10 + ½(100 + 50) × 10 = 1000 + 750 = 1750 J.
  • Car and spring (Ex 5.8). m = 1000 kg, v = 18 km/h = 5 m s⁻¹, k = 6.25 × 10³ N m⁻¹. ½ m v² = ½ k x² ⇒ x = v √(m/k) = 5 × 0.4 = 2.0 m.
  • Slowing neutrons (Ex 5.11). Elastic head-on collision with a nucleus of mass m₂ at rest. With deuterium (m₂ = 2m₁) the neutron keeps (1/3)² = 1/9 of its KE — 8/9 is transferred. With carbon (m₂ = 12m₁) it keeps (11/13)² ≈ 0.716, transferring only about 28%. Hence heavy water is a better moderator.
  • Formula / Key-Facts Sheet

  • W = F d cos θ; W = ∫F dx (area under F–x graph)
  • K = ½ m v²; Kf − Ki = W(net)
  • Gravitational PE = m g h; spring PE = ½ k x²; F = −dV/dx
  • K + V = constant (conservative forces only)
  • P = W/t; P = F·v; 1 hp = 746 W; 1 kWh = 3.6 × 10⁶ J
  • Elastic 1-D (target at rest): v₁f = (m₁ − m₂)v₁i/(m₁ + m₂), v₂f = 2m₁v₁i/(m₁ + m₂)
  • Exam Focus

    Frequent questions: sign of work in given situations (Exercise 5.1-type), work-energy theorem numericals, energy conservation in a pendulum or roller coaster, spring compression, power of a pump or motor, and elastic/inelastic collision numericals (Exercise 5.9–5.12 types).

  • Outline — "Show that mechanical energy is conserved in free fall": at height H, E = mgH; at x below, E = mg(H − x) + ½ m v² with v² = 2gx ⇒ E = mgH.
  • Outline — "Show that in an elastic collision of equal masses the velocities exchange": put m₁ = m₂ in the 1-D formulas ⇒ v₁f = 0, v₂f = v₁i.
  • Outline — power: P = F v; a force of 500 N on a body moving at 4 m s⁻¹ delivers 2000 W.
  • Key Terms

  • Scalar product (अदिश गुणनफल)
  • Work (कार्य)
  • Kinetic energy (गतिज ऊर्जा)
  • Potential energy (स्थितिज ऊर्जा)
  • Work-energy theorem (कार्य-ऊर्जा प्रमेय)
  • Conservative force (संरक्षी बल)
  • Mechanical energy (यांत्रिक ऊर्जा)
  • Spring constant (कमानी स्थिरांक)
  • Power (शक्ति)
  • Watt (वाट)
  • Elastic collision (प्रत्यास्थ संघट्ट)
  • Inelastic collision (अप्रत्यास्थ संघट्ट)
  • Joule (जूल)
  • Hooke's law (हुक का नियम)
  • Common Mistakes

  • Saying no work is done because a force is large — work needs displacement along the force.
  • Forgetting the sign: friction and braking forces do negative work.
  • Treating kWh as a unit of power; it is energy.
  • Assuming kinetic energy is conserved in every collision; only momentum always is.
  • Using mgh for springs or ½kx² for gravity.
  • Counting work done by a body on the road as equal to work done by the road on the body (Ex 5.3 shows it is zero).
  • 💡 Key Learning Points

    • ✓Define work using the scalar product and identify positive, negative and zero work
    • ✓State and apply the work-energy theorem for constant and variable forces
    • ✓Use conservation of mechanical energy with gravitational and spring potential energy
    • ✓Calculate power as P = W/t and P = F·v
    • ✓Analyse elastic and inelastic collisions in one and two dimensions

    👨‍🏫 Teaching Tips

    • →Show zero work by pushing a wall hard and asking what moves
    • →Plot a force–displacement graph on the board and let students find work as area (Ex 5.5)
    • →Use a pendulum to show exchange of kinetic and potential energy
    • →Demonstrate a Newton's cradle for elastic collisions of equal masses
    • →Compare the power of two students climbing the same stairs at different speeds
    • →Discuss why neutrons are slowed better by light nuclei (Ex 5.11)
    • →Link kWh on an electricity bill to joules

    📋 Assessment Questions

    1. State the work-energy theorem and derive it for constant force
    2. When is work done by a force zero? Give three examples
    3. Find the maximum compression of a spring hit by a car of known speed
    4. Show that equal masses exchange velocities in a 1-D elastic collision
    5. Define power and show that P = F·v

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