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A Tale of Three Intersecting Lines – Class 7 Maths Chapter 7 Notes & NCERT PDF

Class 7MathematicsChapter 7NCERT book: Ganita Prakash - Mathematics Class 7

Notes and a simple summary of Chapter 7 of the NCERT Class 7 Mathematics book, with the official chapter PDF, flashcards, an MCQ quiz and an AI tutor for your doubts.

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Chapter 7: A Tale of Three Intersecting Lines

Introduction

A triangle is the most basic closed shape: three vertices (corner points) joined by three sides. We name it by its vertices, in any order — ∆ABC, ∆YZX, ∆WUV — and write its angles ∠CAB, ∠ABC, ∠BCA simply as ∠A, ∠B and ∠C. The chapter begins with a puzzle worth keeping in mind: what happens when the three vertices lie on a straight line? (No triangle forms!)

This chapter is about how to construct triangles, when a triangle is possible at all, the famous angle sum property, altitudes, and types of triangles.

Key Ideas

7.1 Equilateral Triangles

An equilateral triangle has all three sides equal. It is the most symmetric triangle.

To construct one with sides 4 cm, a ruler alone would need many trials. A compass makes it exact — the same trick you used in Grade 6 to mark the top point of a "house" 5 cm from two points.

7.2 Constructing a Triangle When its Sides are Given

For sides 4 cm, 5 cm and 6 cm: draw base AB = 4 cm. Every point 5 cm from A lies on a circle of radius 5 cm centred at A; every point 6 cm from B lies on a circle of radius 6 cm centred at B. The third vertex C must be on both — so C is where the arcs meet.

Triangles with two equal sides are isosceles; with three different sides, scalene.

Are Triangles Possible for any Lengths?

Try 3 cm, 4 cm, 8 cm or 2 cm, 3 cm, 6 cm — the arcs never meet! The book explains why with a tent, a tree and a pole: the straight path from the tent to the tree is always shorter than going via the pole. So in any triangle, each side must be shorter than the sum of the other two.

For 10 cm, 15 cm, 30 cm: 10 < 15 + 30 = 45 and 15 < 30 + 10 = 40, but 30 > 10 + 15 = 25 — the "direct path" is longer than the "roundabout path", which is absurd. No triangle.

Triangle inequality: a set of three lengths satisfies it when each length is smaller than the sum of the other two.

Shortcut: only compare the longest length with the sum of the two smaller ones — the other two comparisons are automatically true.

Why the triangle inequality guarantees a triangle

Take the longest length as base AB and draw circles with the two smaller lengths as radii. Three cases:

  • Sum of radii = AB → circles just touch at a point → no triangle (vertices in a line).
  • Sum of radii < AB → circles don't meet → no triangle.
  • Sum of radii > AB → circles intersect → a triangle exists.
  • For 4, 5, 8: base 8 cm, AX = 4 so BX = 4 cm, which is less than 5 — the circles cross, and a triangle exists.

    Conclusion: if three lengths satisfy the triangle inequality, a triangle exists; if not, it does not.

    7.3 Triangles When Some Sides and Angles are Given

  • Two sides and the included angle (e.g. AB = 5 cm, AC = 4 cm, ∠A = 45°): draw AB, make ∠A at A, mark C on the arm with AC = 4 cm, join BC.
  • Two angles and the included side (e.g. AB = 5 cm, ∠A = 45°, ∠B = 80°): draw AB, draw both angles; where the arms meet is C.
  • When is a triangle impossible with two angles? If ∠A = 40°, the line from B fails to meet line l when it is parallel or bends away. Using co-interior angles on transversal AB, ∠B = 180° − 40° = 140° for parallel lines. So no triangle when ∠B ≥ 140°. The length AB plays no part!

    Rule: a triangle exists with two given angles only when their sum is less than 180°.

    The Angle Sum Property

    For ∆ABC with ∠B = 50°, ∠C = 70°: draw line XY through A parallel to BC. Alternate angles give ∠XAB = 50° and ∠YAC = 70°. These three angles at A make a straight angle, so 50° + ∠BAC + 70° = 180° → ∠BAC = 60°.

    Angle sum property: the three angles of any triangle add up to 180°.

    This parallel-line idea is from *Euclid's The Elements* (Euclid lived around 300 BCE). You can also check it by folding a paper triangle** so the three corners meet on a line.

    Exterior Angles

    Extend side BC to D; ∠ACD is an exterior angle. If ∠A = 50° and ∠B = 60°, then ∠ACB = 70° and ∠ACD = 180° − 70° = 110°, which equals ∠A + ∠B.

    An exterior angle equals the sum of the two opposite interior angles.

    7.4 Altitudes

    The altitude from A is the perpendicular segment AD from A to the opposite side BC; its length is the height of A above BC. Every triangle has three altitudes (AD, BE, CF). In some triangles the altitude falls outside — extend BC and drop the perpendicular to the extended line. Use a set square sliding along a ruler to draw altitudes accurately, or fold a paper triangle so one side lies on itself.

    In a right-angled triangle, a side is itself an altitude.

    7.5 Types of Triangles

  • By sides: equilateral (all equal), isosceles (two equal), scalene (all different).
  • By angles: acute-angled (all three angles acute), right-angled (one 90° angle), obtuse-angled (one obtuse angle).
  • Why can't "acute-angled" mean "has one acute angle"? Because every triangle has at least two acute angles!

    Worked Examples

    Example 1 — Construct ∆ABC with sides 4 cm, 5 cm, 6 cm.

  • Draw base AB = 4 cm.
  • From A, draw an arc of radius 5 cm.
  • From B, draw an arc of radius 6 cm cutting the first arc.
  • Mark the meeting point C; join AC and BC.
  • Example 2 — Can 2, 2, 5 be sides of a triangle? Longest = 5; 2 + 2 = 4 < 5. No. What about 24, 26, 28? 24 + 26 = 50 > 28. Yes.

    Example 3 — Third side for sides 1 and 100. It must be strictly between 100 − 1 = 99 and 100 + 1 = 101, e.g. 99.5, 100, 100.7.

    Example 4 — Find the third angle when two angles are 75° and 45°. 180° − (75° + 45°) = 180° − 120° = 60°.

    Example 5 — In ∆ABC, ∠B = ∠C and ∠A = 50°. ∠B + ∠C = 130°, so ∠B = ∠C = 65°.

    Example 6 — Can 35° and 150° be two angles of a triangle? 35° + 150° = 185° ≥ 180°. No.

    Figure it Out — Hints

  • For "does a triangle exist?", sort the lengths and compare the largest with the sum of the other two.
  • For "all possible third sides", the third side must be greater than the difference and less than the sum of the given two.
  • For "can these two angles form a triangle?", add them — the sum must be below 180°.
  • For "all angles 70°": 3 × 70° = 210° ≠ 180°, so impossible. If two angles are 70°, the third is 40°. If all three are equal, each is 60°.
  • Shortest path in a box: unfold the box flat — the shortest path becomes a straight line on the net.
  • Maths Words

  • Vertex (शीर्ष) — corner point of a triangle
  • Side (भुजा) — segment joining two vertices
  • Equilateral triangle (समबाहु त्रिभुज)
  • Isosceles triangle (समद्विबाहु त्रिभुज)
  • Scalene triangle (विषमबाहु त्रिभुज)
  • Triangle inequality (त्रिभुज असमिका)
  • Included angle (अंतर्गत कोण) — the angle between two given sides
  • Included side (अंतर्गत भुजा) — the side shared by two given angles
  • Angle sum property (कोण योग गुण)
  • Exterior angle (बाह्य कोण)
  • Altitude (शीर्षलंब) — perpendicular from a vertex to the opposite side
  • Acute / right / obtuse-angled triangle (न्यूनकोण / समकोण / अधिककोण त्रिभुज)
  • Arc (चाप), compass (परकार), set square (सेट स्क्वायर)
  • Historical Connections

    The proof of the angle sum property using a parallel line appears in The Elements, attributed to the Greek mathematician Euclid (around 300 BCE) — a reminder that creative ideas, like drawing one extra line, can make a hidden relationship obvious.

    Common Mistakes

  • Checking only one pair in the triangle inequality — or the wrong pair. Always test the longest side.
  • Thinking "sum equal to the longest side" gives a flat but valid triangle — it gives no triangle (the circles only touch).
  • Measuring an altitude to a side instead of perpendicular to it; for obtuse triangles forgetting to extend the base.
  • Calling a triangle "acute-angled" because it has one acute angle.
  • Adding two angles and forgetting that a sum equal to 180° also means no triangle.
  • Maths in Daily Life

    The triangle inequality is why a straight road is shorter than a detour. Carpenters and engineers use triangles because a triangle with fixed sides cannot change shape — that's why bridges, roof trusses and cycle frames are full of triangles.

    💡 Key Learning Points

    • ✓Construct triangles with a compass and ruler from three sides, from two sides and the included angle, and from two angles and the included side
    • ✓Use the triangle inequality (each side < sum of the other two; test the longest side) to decide whether a triangle exists
    • ✓Two angles can belong to a triangle only if their sum is less than 180°; the included side does not matter
    • ✓Prove and use the angle sum property (180°) with a line parallel to the base, and find exterior angles
    • ✓Draw altitudes with a set square and classify triangles by sides (equilateral, isosceles, scalene) and by angles (acute, right, obtuse)

    👨‍🏫 Teaching Tips

    • →Act out the tent–tree–pole story in the playground with ropes so students feel why a detour is always longer than a straight path
    • →Give each group straws cut to lengths like 3-4-8, 2-3-6 and 4-5-6; they record which sets close into a triangle and discover the rule themselves
    • →Show the three circle cases (touch, miss, intersect) with two compasses on the board before stating the conclusion
    • →Have students tear the three corners of a paper triangle and line them up, then fold a paper triangle, to confirm the 180° angle sum
    • →Let students slide a set square along a ruler to draw altitudes, including one for an obtuse triangle where the base must be extended
    • →Run a quick 'Possible or Not?' game: call out three lengths or two angles and students show thumbs up/down with a reason
    • →Use the 'Shortest Path in a Box' spider puzzle with a real cardboard box as an enrichment challenge

    📋 Assessment Questions

    1. Can the student construct a triangle from three given sides and explain why the arcs' meeting point is the third vertex?
    2. Can the student decide, with the longest-side check, whether a set like 5, 10, 12 or 3, 6, 9 forms a triangle?
    3. Can the student find a missing angle and an exterior angle using the 180° property?
    4. Can the student state the condition for two angles to form a triangle and give an example where it fails?
    5. Can the student draw an altitude correctly, including for an obtuse triangle, and classify a triangle by both sides and angles?

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