Question 1:

Balbharti Maharashtra State Board Class 6 Maths Solutions covers the Std 6 Maths Chapter 4 Operations on Fractions Class 6 Practice Set 13 Answers Solutions.

Question 2:

Write the reciprocals of the following numbers:

Solution:

Question 3:

Carry out the following Divisions:
i. $\frac{2}{3} \div \frac{1}{4}$
ii. $\frac{5}{9} \div \frac{3}{2}$
iii. $\frac{3}{7} \div \frac{5}{11}$
iv. $\frac{11}{12} \div \frac{4}{7}$
Solution:
i. $\frac{2}{3} \div \frac{1}{4}$

ii. $\frac{5}{9} \div \frac{3}{2}$

iii. $\frac{3}{7} \div \frac{5}{11}$

iv. $\frac{11}{12} \div \frac{4}{7}$

Question 4:

There were 420 students participating in the Swachh Bharat Campaign. They cleaned $\frac { 42 }{ 75 }$ part of the town, Sevagram. What part of Sevagram did each student clean if the work was equally shared by all?
Solution:
Total number of students = 420
Part of town cleaned by all the students = $\frac { 42 }{ 75 }$
∴ Part of town cleaned by one student

∴ Part of town cleaned bv one student is $\frac { 1 }{ 750 }$

Question 5:

Ramanujan’s Magic square. (Textbook pg. no. 28)

Obtain and read a biography of the great Indian mathematician Srinivasa Ramanujan.
Solution:
Sum of the numbers in each row:
i. 22 + 12 + 18 + 87 = 139
ii. 88 + 17 + 9 + 25 = 139
iii. 10 + 24 + 89 + 16 = 139
iv. 19 + 86 + 23 + 11 = 139

Sum of the numbers along the diagonals:
i. 22 + 17 + 89 + 11 = 139
ii. 87 + 9 + 24 + 19 = 139

Sum of the numbers in each column:
i. 22 + 88 + 10 + 19 = 139
ii. 12 + 17 + 24 + 86 = 139
iii. 18 + 9 + 89 + 23 = 139
iv. 87 + 25 + 16 + 11 = 139

∴ We observe that the sum of the numbers in each of the rows, the columns and along each diagonal remains the same every time. The numbers in the first row 22 – 12 – 1887 is the birth date of Srinivasa Ramanujan.