Practice Set 27 Class 7 Answers Chapter 6 Indices Maharashtra Board

Balbharti Maharashtra State Board Class 7 Maths Solutions covers the 7th Std Maths Practice Set 27 Answers Solutions Chapter 6 Indices.

Indices Class 7 Maths Chapter 6 Practice Set 27 Solutions Maharashtra Board

Std 7 Maths Practice Set 27 Solutions Answers

Question 1.
Simplify:
i. 7 ⁴ × 7 ²
ii. (-11) ⁵ × (-11) ²
iii. $\left(\frac{6}{7}\right)^{3} \times\left(\frac{6}{7}\right)^{5}$
iv. $\left(-\frac{3}{2}\right)^{5} \times\left(-\frac{3}{2}\right)^{3}$
v. a ¹⁶ × a ⁷
vi. $\left(\frac{\mathrm{P}}{5}\right)^{3} \times\left(\frac{\mathrm{P}}{5}\right)^{7}$
Solution:
i. 7 ⁴ × 7 ²
= 7 ⁴⁺²
= 7 ⁶

ii. (-11) ⁵ × (-11) ²
= (-11) ⁵⁺²
= (-11) ⁷

iii. $\left(\frac{6}{7}\right)^{3} \times\left(\frac{6}{7}\right)^{5}$
$=\left(\frac{6}{7}\right)^{3+5}=\left(\frac{6}{7}\right)^{8}$

iv. $\left(-\frac{3}{2}\right)^{5} \times\left(-\frac{3}{2}\right)^{3}$
$=\left(-\frac{3}{2}\right)^{5+3}=\left(-\frac{3}{2}\right)^{8}$

v. a ¹⁶ × a ⁷
= a ¹⁶⁺⁷
= a ²³

vi. $\left(\frac{\mathrm{P}}{5}\right)^{3} \times\left(\frac{\mathrm{P}}{5}\right)^{7}$
$=\left(\frac{\mathrm{P}}{5}\right)^{3+7}=\left(\frac{\mathrm{P}}{5}\right)^{10}$