11th Commerce Maths 1 Chapter 9 Exercise 9.1 Answers Maharashtra Board

Differentiation Class 11 Commerce Maths 1 Chapter 9 Exercise 9.1 Answers Maharashtra Board

Balbharati Maharashtra State Board 11th Commerce Maths Solution Book Pdf Chapter 9 Differentiation Ex 9.1 Questions and Answers.

Std 11 Maths 1 Exercise 9.1 Solutions Commerce Maths

I. Find the derivatives of the following functions w.r.t. x.

Question 1.
x 12
Solution:
Let y = x 12
Differentiating w.r.t. x, we get
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-I-Q1

Question 2.
x -9
Solution:
Let y = x -9
Differentiating w.r.t. x, we get
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-I-Q2

Maharashtra-Board-Solutions

Question 3.
\(x^{\frac{3}{2}}\)
Solution:
Let y = \(x^{\frac{3}{2}}\)
Differentiating w.r.t. x, we get
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-I-Q3

Question 4.
7x√x
Solution:
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-I-Q4

Question 5.
3 5
Solution:
Let y = 3 5
Differentiating w.r.t. x, we get
\(\frac{d y}{d x}=\frac{d}{d x} 3^{5}=0\) …..[3 5 is a constant]

II. Differentiate the following w.r.t. x.

Question 1.
x 5 + 3x 4
Solution:
Let y = x 5 + 3x 4
Differentiating w.r.t. x, we get
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-II-Q1

Maharashtra-Board-Solutions

Question 2.
x√x + log x – e x
Solution:
Let y = x√x + log x – e x
= \(x^{\frac{3}{2}}+\log x-e^{x}\)
Differentiating w.r.t. x, we get
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-II-Q2

Question 3.
\(x^{\frac{5}{2}}+5 x^{\frac{7}{5}}\)
Solution:
Let y = \(x^{\frac{5}{2}}+5 x^{\frac{7}{5}}\)
Differentiating w.r.t. x, we get
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-II-Q3

Question 4.
\(\frac{2}{7} x^{\frac{7}{2}}+\frac{5}{2} x^{\frac{2}{5}}\)
Solution:
Let y = \(\frac{2}{7} x^{\frac{7}{2}}+\frac{5}{2} x^{\frac{2}{5}}\)
Differentiating w.r.t. x, we get
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-II-Q4

Question 5.
\(\sqrt{x}\left(x^{2}+1\right)^{2}\)
Solution:
Let y = \(\sqrt{x}\left(x^{2}+1\right)^{2}\)
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-II-Q5

III. Differentiate the following w.r.t. x.

Question 1.
x 3 log x
Solution:
Let y = x 3 log x
Differentiating w.r.t. x, we get
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-III-Q1

Maharashtra-Board-Solutions

Question 2.
\(x^{\frac{5}{2}} e^{x}\)
Solution:
Let y = \(x^{\frac{5}{2}} e^{x}\)
Differentiating w.r.t. x, we get
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-III-Q2

Question 3.
e x log x
Solution:
Let y = e x log x
Differentiating w.r.t. x, we get
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-III-Q3

Question 4.
x 3 . 3 x
Solution:
Let y = x 3 . 3 x
Differentiating w.r.t. x, we get
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-III-Q4

IV. Find the derivatives of the following w.r.t. x.

Question 1.
\(\frac{x^{2}+a^{2}}{x^{2}-a^{2}}\)
Solution:
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-IV-Q1

Question 2.
\(\frac{3 x^{2}+5}{2 x^{2}-4}\)
Solution:
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-IV-Q2
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-IV-Q2.1

Maharashtra-Board-Solutions

Question 3.
\(\frac{\log x}{x^{3}-5}\)
Solution:
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-IV-Q3

Question 4.
\(\frac{3 e^{x}-2}{3 e^{x}+2}\)
Solution:
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-IV-Q4
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-IV-Q4.1

Question 5.
\(\frac{x \mathrm{e}^{x}}{x+\mathrm{e}^{x}}\)
Solution:
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-IV-Q5

V. Find the derivatives of the following functions by the first principle:

Question 1.
3x 2 + 4
Solution:
Let f(x) = 3x 2 + 4
∴ f(x + h) = 3(x + h) 2 + 4
= 3(x 2 + 2xh + h 2 ) + 4
= 3x 2 + 6xh + 3h 2 + 4
By first principle, we get
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-V-Q1
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-V-Q1.1

Maharashtra-Board-Solutions

Question 2.
x√x
Solution:
Let f(x) = x√x
∴ f(x + h) = \((x+h)^{\frac{3}{2}}\)
By first principle, we get
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-V-Q2

Question 3.
\(\frac{1}{2 x+3}\)
Solution:
Let f(x) = \(\frac{1}{2 x+3}\)
∴ f(x + h) = \(\frac{1}{2(x+\mathrm{h})+3}=\frac{1}{2 x+2 \mathrm{~h}+3}\)
By first principle, we get
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-V-Q3
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-V-Q3.1

Maharashtra-Board-Solutions

Question 4.
\(\frac{x-1}{2 x+7}\)
Solution:
Let f(x) = \(\frac{x-1}{2 x+7}\)
∴ f(x + h) = \(\frac{x+\mathrm{h}-1}{2(x+\mathrm{h})+7}=\frac{x+\mathrm{h}-1}{2 x+2 \mathrm{~h}+7}\)
By first principle, we get
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-9-Differentiation-Ex-9.1-V-Q4