12th Commerce Maths 1 Chapter 3 Exercise 3.2 Answers Maharashtra Board

Differentiation Class 12 Commerce Maths 1 Chapter 3 Exercise 3.2 Answers Maharashtra Board

Balbharati Maharashtra State Board 12th Commerce Maths Solution Book Pdf Chapter 3 Differentiation Ex 3.2 Questions and Answers.

Std 12 Maths 1 Exercise 3.2 Solutions Commerce Maths

1. Find the rate of change of demand (x) of a commodity with respect to price (y) if:

Question 1.
y = 12 + 10x + 25x 2
Solution:
Given y = 12 + 10x + 25x 2
Maharashtra-Board-12th-Commerce-Maths-Solutions-Chapter-3-Differentiation-Ex-3.2-I-Q1
Hence, the rate of change of demand (x) with respect to price (y) \(=\frac{d x}{d y}=\frac{1}{10+50 x}\)

Question 2.
y = 18x + log(x – 4)
Solution:
Given y = 18x + log (x – 4)
Maharashtra-Board-12th-Commerce-Maths-Solutions-Chapter-3-Differentiation-Ex-3.2-I-Q2
Hence, the rate of change of demand (x) with respect to price (y) \(=\frac{d x}{d y}=\frac{x-4}{18 x-71}\)

Maharashtra-Board-Solutions

Question 3.
y = 25x + log(1 + x 2 )
Solution:
Given y = 25x + log(1 + x 2 )
Maharashtra-Board-12th-Commerce-Maths-Solutions-Chapter-3-Differentiation-Ex-3.2-I-Q3
Hence, the rate of change of demand (x) with respect to price (y) \(\frac{d x}{d y}=\frac{1+x^{2}}{25 x^{2}+2 x+25}\)

2. Find the marginal demand of a commodity where demand is x and price is y.

Question 1.
y = xe -x + 7
Solution:
Maharashtra-Board-12th-Commerce-Maths-Solutions-Chapter-3-Differentiation-Ex-3.2-II-Q1
Maharashtra-Board-12th-Commerce-Maths-Solutions-Chapter-3-Differentiation-Ex-3.2-II-Q1.1

Question 2.
y = \(\frac{x+2}{x^{2}+1}\)
Solution:
Maharashtra-Board-12th-Commerce-Maths-Solutions-Chapter-3-Differentiation-Ex-3.2-II-Q2

Maharashtra-Board-Solutions

Question 3.
y = \(\frac{5 x+9}{2 x-10}\)
Solution:
Maharashtra-Board-12th-Commerce-Maths-Solutions-Chapter-3-Differentiation-Ex-3.2-II-Q3