Practice Set 11 Class 6 Answers Maths Chapter 4 Operations on Fractions Maharashtra Board

Operations on Fractions Class 6 Maths Chapter 4 Practice Set 11 Solutions Maharashtra Board

Std 6 Maths Practice Set 11 Solutions Answers

Question 11.
What fractions do the points A and B show on the number lines below?
Maharashtra-Board-Class-6-Maths-Solutions-Chapter-4-Operations-on-Fractions-Practice-Set-11-1
Solution:
(1) Each unit is divided in 6 parts
A is 5th division from 0
∴ \(A=\frac { 5 }{ 6 }\)

B is 10th division from 0
∴ \(B=\frac { 10 }{ 6 }\)

(2) Each unit is divided in 5 parts
A is 3rd division from 0
∴ \(A=\frac { 3 }{ 5 }\)

B is 7th division from 0
∴ \(B=\frac { 7 }{ 5 }\)

(3) Each unit is divided in 7 parts
A is 10th division from 0
∴ \(A=\frac { 10 }{ 7 }\)

B is 3rd division from 0
∴ \(B=\frac { 3 }{ 7 }\)

Question 2.
Show the following fractions on the number line:
i. \(\frac{3}{5}, \frac{6}{5}, 2 \frac{3}{5}\)
ii. \(\frac{3}{4}, \frac{5}{4}, 2 \frac{1}{4}\)
Solution:
i. \(\frac{3}{5}, \frac{6}{5}, 2 \frac{3}{5}\)
Maharashtra-Board-Class-6-Maths-Solutions-Chapter-4-Operations-on-Fractions-Practice-Set-11-2

ii. \(\frac{3}{4}, \frac{5}{4}, 2 \frac{1}{4}\)
Maharashtra-Board-Class-6-Maths-Solutions-Chapter-4-Operations-on-Fractions-Practice-Set-11-3

Maharashtra Board Class 6 Maths Chapter 4 Operations on Fractions Practice Set 11 Intext Questions and Activities

Question 1.
If we want to show the fractions \(\frac{3}{10}, \frac{9}{20}, \frac{19}{40}\) on the number line, how big should the unit be? (Textbook pg. no. 24)
Solution:
The denominators of the given fractions are not equal.
The numbers in the denominators 10, 20 and 40 have common multiple 40.
∴ Making the denominators equal, we get
Maharashtra-Board-Class-6-Maths-Solutions-Chapter-4-Operations-on-Fractions-Practice-Set-11-4
∴ To represent these fractions on the numbers line, each main unit should be divided into 40 equal sub-units.
Maharashtra-Board-Class-6-Maths-Solutions-Chapter-4-Operations-on-Fractions-Practice-Set-11-5
Therefore,
\(\frac{3}{10}=\frac{12}{40}\) is represented on 12th mark from 0.
\(\frac{9}{20}=\frac{18}{40}\) is represented on 18th mark from 0 and
\(\frac { 19 }{ 40 }\) is represented on 19 mark from 0.

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