11th Commerce Maths 2 Chapter 8 Exercise 8.3 Answers Maharashtra Board

Linear Inequations Class 11 Commerce Maths 2 Chapter 8 Exercise 8.3 Answers Maharashtra Board

Balbharati Maharashtra State Board 11th Commerce Maths Solution Book Pdf Chapter 8 Linear Inequations Ex 8.3 Questions and Answers.

Std 11 Maths 2 Exercise 8.3 Solutions Commerce Maths

Find the graphical solution for the following system of linear inequations.

Question 1.
x – y ≤ 0, 2x – y ≥ -2
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-8-Linear-Inequations-Ex-8.3-Q1
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-8-Linear-Inequations-Ex-8.3-Q1.1
The shaded portion represents the graphical solution.

Question 2.
2x + 3y ≥ 12, -x + y ≤ 3, x ≤ 4, y ≥ 3
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-8-Linear-Inequations-Ex-8.3-Q2
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-8-Linear-Inequations-Ex-8.3-Q2.1
The shaded portion represents the graphical solution.

Maharashtra-Board-Solutions

Question 3.
3x + 2y ≤ 1800, 2x + 7y ≤ 1400
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-8-Linear-Inequations-Ex-8.3-Q3
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-8-Linear-Inequations-Ex-8.3-Q3.1
The shaded portion represents the graphical solution.

Question 4.
0 ≤ x ≤ 350, 0 ≤ y ≤ 150
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-8-Linear-Inequations-Ex-8.3-Q4
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-8-Linear-Inequations-Ex-8.3-Q4.1
The shaded portion represents the graphical solution.

Question 5.
\(\frac{x}{60}+\frac{y}{90}\) ≤ 1, \(\frac{x}{120}+\frac{y}{75}\) ≤ 1, x ≥ 0, y ≥ 0
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-8-Linear-Inequations-Ex-8.3-Q5
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-8-Linear-Inequations-Ex-8.3-Q5.1
The shaded portion represents the graphical solution.

Maharashtra-Board-Solutions

Question 6.
3x + 2y ≤ 24, 3x + y ≥ 15, x ≥ 4
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-8-Linear-Inequations-Ex-8.3-Q6
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-8-Linear-Inequations-Ex-8.3-Q6.1
The shaded portion represents the graphical solution.

Question 7.
2x + y ≥ 8, x + 2y ≥ 10, x ≥ 0, y ≥ 0
Solution:
To find a graphical solution, construct the table as follows:
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-8-Linear-Inequations-Ex-8.3-Q7
Maharashtra-Board-11th-Commerce-Maths-Solutions-Chapter-8-Linear-Inequations-Ex-8.3-Q7.1
Shaded portion represents the graphical solution.