Problems on ages — Quantitative aptitude for kids

The method

Same years for everyone — “n years later or earlier, every age changes by n — the difference never changes”

1. “k times as old”: the younger is 1 part, the older is k parts.
2. n years ago or later: change every age by n before using the clue.
3. Sum and difference: younger = (sum − difference) ÷ 2.
4. For “in a years … b years ago”, let the age be x and solve.

Use it for: Age puzzles in aptitude and scholarship tests, and early algebra in Class 6–8.

Worked example: 4 years ago, Meera’s mother was four times as old as Meera. The mother is 36 years old now. How old is Meera now? → 12

✏️ Practice

Work it out in your head or on paper, then tap your answer — or type it and press Check. Stuck? Press “Show me how”.

🏁 Lesson 17 test

20 questions. Check each answer, then go to the next one. Get 16 or more right to pass.

🏅 Sign in with Google to earn the 🎂 Age Solver badge when you pass — and a certificate when you finish all 10 lessons of Part 2 · Everyday maths. You can still take the test without signing in.

🖨️ Problems on Ages Worksheet

• Worksheet set 1 (PDF)
• Worksheet set 2 (PDF)
• Worksheet set 3 (PDF)