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Textbook: Science and Technology Part 1 – Class 10 (Balbharati, official free PDF)
Learn why apples fall, how planets stay in orbit, what g is and why it changes, mass vs weight, free fall and escape velocity.
Every object in the universe pulls every other object towards itself. Newton realised this when he wondered why apples always drop straight down. He guessed that the same pull of the earth that brings an apple down also keeps the moon moving around us. This pull is called gravitation, and it is the main idea of this chapter.
Anything moving in a circle needs a force pointing to the centre, called the centripetal force. Kepler had already found three rules for how planets move around the Sun by studying careful records of their positions. Newton used these rules, especially the third one, to show that the force on a planet must fall off as the square of its distance from the Sun.
This led to Newton's universal law of gravitation: the force between two masses is proportional to the product of the masses and inversely proportional to the square of the distance between them. The constant G is tiny, so the pull between two people is too small to notice, but the huge mass of the earth makes its pull strong.
The earth's pull gives every falling object the same acceleration, g, about 9.8 m/s2 near the surface. g is a little more at the poles than at the equator, and it becomes smaller as we go up or deep down. Mass stays the same everywhere, but weight (mg) changes from place to place, which is why we would weigh much less on the moon.
An object moving only under gravity is in free fall, and we can use the equations of motion with a = g. Throw something fast enough, about 11.2 km/s from the earth, and it never comes back. That speed is the escape velocity, and rockets going to the moon or Mars must cross it.
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A 0.2 kg stone tied to a string moves in a circle of radius 0.5 m with a speed of 3 m/s. Find the centripetal force.
Answer: F = 3.6 N, directed towards the centre of the circle
Planet P goes round a star in time T at distance r. Planet Q orbits the same star at distance 4r. Find the period of Q.
Answer: The period of Q is 8T (eight times that of P)
Two students of masses 60 kg and 50 kg sit 2 m apart. Find the gravitational force between them. (G = 6.67 × 10-11 N m2 kg-2)
Answer: F ≈ 5.0 × 10-8 N, far too small to notice
A planet has twice the mass of the earth and twice its radius. Find g on its surface if g on the earth is 9.8 m/s2.
Answer: gp = 4.9 m/s2
A student has a mass of 60 kg. Find her mass and weight on the earth and on the moon. (g on earth = 9.8 m/s2, g on moon = 1/6 of that on earth)
Answer: Mass 60 kg on both; weight 588 N on earth and 98 N on the moon
A stone is dropped from the top of a 45 m high building. Taking g = 10 m/s2, find the time it takes to reach the ground and its speed just before hitting the ground.
Answer: Time = 3 s; speed on reaching the ground = 30 m/s
A planet has radius 3.6 × 106 m and g = 5 m/s2 at its surface. Find the escape velocity.
Answer: vesc = 6000 m/s = 6 km/s
| What | Formula | Symbols |
|---|---|---|
| Centripetal force | F = m v2/r | F = force towards the centre (N), m = mass (kg), v = speed (m/s), r = radius of circle (m) |
| Speed in a circular orbit | v = 2πr/T | r = radius of orbit (m), T = period of revolution (s), v = speed (m/s) |
| Kepler's third law | T2/r3 = K | T = period of revolution (s), r = mean distance from the Sun (m), K = constant for all planets of the same star |
| Newton's universal law of gravitation | F = G m1m2/d2 | F = gravitational force (N), m1, m2 = masses (kg), d = distance between centres (m), G = 6.67 × 10-11 N m2 kg-2 |
| Acceleration due to gravity at distance r | g = GM/r2 | g in m/s2, M = mass of the earth (kg), r = distance from the earth's centre (m) |
| Acceleration due to gravity on the surface | g = GM/R2 | R = radius of the earth (6.4 × 106 m), M = 6 × 1024 kg; g ≈ 9.8 m/s2 |
| Weight | W = m g | W = weight (N), m = mass (kg), g = acceleration due to gravity (m/s2) |
| Free fall equations | v = g t; s = ½ g t2; v2 = 2 g s | starting from rest: v = final velocity (m/s), t = time (s), s = distance fallen (m), g in m/s2 |
| Maximum height of a body thrown up | h = u2/2g | u = initial upward velocity (m/s), h = maximum height (m) |
| Gravitational potential energy at height h | PE = −GMm/(R + h) | M, R = mass (kg) and radius (m) of the earth, m = mass of the object (kg), h = height above surface (m); PE in joule |
| Escape velocity | vesc = √(2GM/R) = √(2gR) | vesc in m/s; M, R = mass and radius of the planet; for the earth about 11.2 km/s |
Read the question, answer it in your head, then tap the card to check. 20 cards.
15 questions. Tap an option — you will see at once if it is right and why.
1. The SI unit of the universal gravitational constant G is:
Answer: B. From F = Gm1m2/d2, G = Fd2/(m1m2), so its unit is N m2 kg-2.
2. The force that keeps the moon moving around the earth acts:
Answer: C. The earth's gravity acts as the centripetal force, which always points towards the centre of the orbit, i.e. the earth.
3. According to Kepler's second law, a planet moves fastest when it is:
Answer: A. Equal areas are swept in equal times, so when the planet is closer, it must cover a longer arc in the same time, i.e. move faster.
4. If the distance between two bodies is made 3 times, the gravitational force becomes:
Answer: D. F ∝ 1/d2, so tripling d makes F become 1/32 = 1/9 of its value.
5. The value of g is highest at:
Answer: C. The earth's radius is smallest at the poles, so g = GM/R2 is largest there (about 9.832 m/s2).
6. A boy has a mass of 50 kg. His weight on the earth (g = 9.8 m/s2) is:
Answer: B. W = mg = 50 × 9.8 = 490 N. Weight is a force, so it is in newton.
7. Which quantity remains the same on the earth and on the moon?
Answer: A. Mass is the amount of matter, which does not depend on location. The other quantities change.
8. A stone is dropped from rest. Taking g = 10 m/s2, its speed after 3 s is:
Answer: D. v = u + gt = 0 + 10 × 3 = 30 m/s.
9. A ball is thrown up with a speed of 20 m/s (g = 10 m/s2). The maximum height reached is:
Answer: B. h = u2/2g = 400/20 = 20 m.
10. As we go deep inside the earth, the value of g:
Answer: C. Although r decreases, the mass pulling the object also decreases, so overall g decreases and becomes zero at the centre.
11. The escape velocity from the surface of the earth is about:
Answer: D. vesc = √(2gR) = √(2 × 9.8 × 6.4 × 106) ≈ 11.2 km/s.
12. A heavy iron ball and a light wooden ball of the same size are dropped together in vacuum from the same height. Then:
Answer: A. In free fall all bodies have the same acceleration g, so they land together.
13. Astronauts in an orbiting space station feel weightless because:
Answer: C. g at the station is only about 11% less than on the surface; weightlessness arises because everything there is falling freely together.
14. A planet has the same mass as the earth but half its radius. g on its surface is:
Answer: B. g = GM/R2; halving R makes R2 one-fourth, so g becomes 4 times.
15. Gravitational potential energy of an object at a height h above the earth's surface is:
Answer: D. Taking potential energy as zero at infinity, it is negative at any finite distance, −GMm/(R + h).
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