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Textbook: Science and Technology Part 1 – Class 10 (Balbharati, official free PDF)
Discover how current produces heat and magnetism, Joule's law, kWh units, motors, electromagnetic induction, AC/DC and generators.
When you switch on a geyser, a fan or a bulb, the same electric current does very different jobs. In this chapter you find out where the energy comes from. The cell or mains supply pushes charge through a resistor, and the work done on that charge turns into heat, light or motion. The rate of this energy transfer is electrical power, P = VI, measured in watts.
The heating effect follows Joule's law: H = I2Rt. Heaters and irons use high-resistance nichrome coils, while bulbs use tungsten filaments that glow white-hot. Your electricity bill counts energy in 'units', where one unit is one kilowatt hour. Too much current from a short circuit or overloading can start a fire, so fuse wires and MCBs cut the supply in time.
In 1820 Oersted noticed that a compass needle turns near a current-carrying wire. Current creates a magnetic field! Around a straight wire the field lines are circles, found by the right hand thumb rule. A loop strengthens the field at its centre, and a solenoid behaves just like a bar magnet with a uniform field inside.
A current-carrying wire placed in a magnetic field feels a force, whose direction is given by Fleming's left hand rule. This idea runs the electric motor in your mixer and ceiling fan, and also the galvanometer, ammeter and voltmeter. The split ring reverses the current every half turn so the coil keeps spinning in one direction.
Faraday reversed the idea in 1831: a changing magnetic field through a coil produces a current. This is electromagnetic induction, and Fleming's right hand rule gives the direction of the induced current. Generators use it to turn mechanical energy into electricity. Slip rings give alternating current (AC, 50 Hz in India), while a split ring gives direct current (DC).
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An electric kettle is rated 1210 W, 220 V. Find the current it draws and the resistance of its heating element.
Answer: Current = 5.5 A, resistance = 40 Ω
A current of 2 A flows through a 25 Ω resistor for 2 minutes. How much heat is produced?
Answer: 12000 J (12 kJ)
A 1.5 kW geyser runs 40 minutes every day. Find the units used in 30 days and the cost at Rs 6 per unit.
Answer: 30 units; cost Rs 180
| What | Formula | Symbols |
|---|---|---|
| Electrical power | P = V I = W/t | P = power (W), V = potential difference (V), I = current (A), W = work/energy (J), t = time (s) |
| Ohm's law | V = I R | V = potential difference (V), I = current (A), R = resistance (Ω) |
| Power in terms of resistance | P = I2R = V2/R | P in watt, I in ampere, R in ohm, V in volt |
| Heat produced (general) | H = V I t = V2t/R | H = heat (J), V in volt, I in ampere, t in second, R in ohm |
| Joule's law of heating | H = I2 R t | H = heat (J), I = current (A), R = resistance (Ω), t = time (s) |
| Electric current | I = Q/t | I = current (A), Q = charge (C), t = time (s) |
| Commercial unit of energy | 1 kWh = 1000 W × 3600 s = 3.6 × 106 J | 1 kWh is called 1 unit on the electricity bill |
| Electrical energy used | E (kWh) = P (kW) × t (h) | P = power in kilowatt, t = time in hours |
| Frequency of AC in India | f = 50 Hz, time for one cycle T = 1/f = 1/50 s | f = frequency (hertz), T = time period (s) |
Read the question, answer it in your head, then tap the card to check. 20 cards.
15 questions. Tap an option — you will see at once if it is right and why.
1. The SI unit of electrical power is:
Answer: B. Power is energy per second; 1 W = 1 J/s.
2. A bulb rated 100 W, 220 V has a resistance of:
Answer: C. R = V2/P = 48400/100 = 484 Ω.
3. A heater of 2 kW runs for 3 hours. Electrical energy used is:
Answer: A. E = P × t = 2 kW × 3 h = 6 kWh = 6 units.
4. A current of 3 A flows through a 10 Ω resistor for 5 s. Heat produced is:
Answer: D. H = I2Rt = 9 × 10 × 5 = 450 J.
5. 1 kWh is equal to:
Answer: A. 1 kWh = 1000 W × 3600 s = 3.6 × 106 J.
6. An 880 W iron is used on a 220 V supply. The current through it is:
Answer: D. I = P/V = 880/220 = 4 A.
7. The coil in an electric heater is made of:
Answer: B. Nichrome has high resistivity and does not oxidise easily when hot.
8. At a fixed voltage, if a heater coil is cut to half its length and used, the power becomes:
Answer: C. Resistance halves; P = V2/R, so power doubles.
9. The magnetic field lines around a long straight current-carrying wire are:
Answer: A. Iron filings form concentric circles in a plane perpendicular to the wire.
10. Inside a long current-carrying solenoid, the magnetic field is:
Answer: C. Field lines inside are parallel, so the field is uniform.
11. In Fleming's left hand rule, the middle finger shows the direction of:
Answer: D. Index finger – field, middle finger – current, thumb – force.
12. An electric motor converts:
Answer: B. A motor uses current to produce rotation.
13. Which scientist showed in 1831 that a moving magnet can produce current in a conductor?
Answer: C. Michael Faraday discovered electromagnetic induction in 1831.
14. In an AC generator, the coil ends are connected to:
Answer: B. Slip rings keep each arm joined to the same brush, so the external current alternates.
15. The time taken for one cycle of AC supply in India is:
Answer: D. Frequency is 50 Hz, so one cycle takes 1/50 s = 0.02 s.
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