Problem Set 49 – Perimeter Formulas and Word ProblemsClass 5 Maths · Chapter 12 Perimeter and Area · Problem Set 49 – Maharashtra Board

Textbook: Mathematics – Class 5 (Balbharati, official free PDF) · pages 69–70

Instead of adding four sides every time, use a short rule: 2 × length + 2 × breadth for a rectangle and 4 × side for a square. Then solve fence and running problems.

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Summary: Problem Set 49 – Perimeter Formulas and Word Problems

A rectangle has two lengths and two breadths, so its perimeter = 2 × length + 2 × breadth.

A square has four equal sides, so its perimeter = 4 × length of one side.

Going once round a field covers its perimeter. Going round several times means multiplying the perimeter by the number of rounds.

A double or triple fence needs 2 or 3 times the perimeter of wire. Cost = length of wire × cost of 1 metre.

Change long distances into kilometres: 1000 m = 1 km, so 4800 m = 4 km 800 m.

Key points to remember

  • Rectangle: P = 2 × length + 2 × breadth
  • Square: P = 4 × side
  • Triangle: add the 3 sides
  • One round = one perimeter
  • n rounds = n × perimeter
  • Triple fence = 3 × perimeter
  • Cost = metres of wire × rate per metre
  • 1000 m = 1 km
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